MCQ
यदि $\cot ^{-1}\left[(\cos \alpha)^{1 / 2}\right]-\tan ^{-1}\left[(\cot \alpha)^{1 / 2}\right]=x$ तब $\sin x=$
  • $\tan ^2 \frac{\alpha}{2}$
  • B
    $\cot ^2 \frac{\alpha}{2}$
  • C
    $\tan \alpha$
  • D
    $\cot \frac{\alpha}{2}$

Answer

Correct option: A.
$\tan ^2 \frac{\alpha}{2}$
(A)

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