MCQ
यदि $\cot ^{-1}\left[(\cos \alpha)^{1 / 2}\right]-\tan ^{-1}\left[(\cot \alpha)^{1 / 2}\right]=x$ तब $\sin x=$
- ✓$\tan ^2 \frac{\alpha}{2}$
- B$\cot ^2 \frac{\alpha}{2}$
- C$\tan \alpha$
- D$\cot \frac{\alpha}{2}$
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