Question
यदि ${\left( {\frac{{1 + i}}{{1 - i}}} \right)^x} = 1,$ तब
==> ${\left( {\frac{{1 + {i^2} + 2i}}{{1 + 1}}} \right)^x} = 1\,\, \Rightarrow \,{i^x} = 1\,$
$\therefore x = 4n,\,n \in {I^ + }$.
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$f(x)=(4 a-3)\left(x+\log _{e} 5\right)+2(a-7) \cot \left(\frac{x}{2}\right) \sin ^{2}\left(\frac{x}{2}\right)$ $x \neq 2 n \pi, n \in N$ के क्रांतिक बिन्दु है