MCQ
यदि $sin^{-1} x = y,$ तब
  • $-\frac{\pi}{2}$ < y < $\frac{\pi}{2}$
  • B
    0 < y < $\pi$
  • C
    $\frac{\pi}{2} \leq$ y $ \leq \frac{\pi}{2}$
  • D
    $0 \leq y \leq \pi$

Answer

Correct option: A.
$-\frac{\pi}{2}$ < y < $\frac{\pi}{2}$
चूँकि sin$^{-1}$ x का परिसर $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ है, इसलिए $-\frac{\pi}{2} \leq$ y $ \leq \frac{\pi}{2}$

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