Question
यदि $\sin A = \sin B$ तथा $\cos A = \cos B,$ तब
$\frac{{\sin A}}{{\sin B}} = \frac{{\cos A}}{{\cos B}}\, $
$\Rightarrow \,\,\sin A\,\cos B - \cos A\,\sin B = 0$
$ \Rightarrow \,\,\sin \,(A - B) = 0$, अत: $\sin \,\left( {\frac{{A - B}}{2}} \right) = 0.$
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