Question
यदि $\sin \left( {{{\sin }^{ - 1}}\frac{1}{5} + {{\cos }^{ - 1}}x} \right) = 1$ तो $ x =$
$\therefore \,\,{\sin ^{ - 1}}\frac{1}{5} = \frac{\pi }{2} - {\cos ^{ - 1}}x = {\sin ^{ - 1}}x$
$\therefore \,\,\,x = \frac{1}{5}$.
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