MCQ
यदि $x \sqrt{1+y}+y \sqrt{1+x}=0$ तब $\frac{d y}{d x}=$
  • A
    $\frac{x+1}{x}$
  • B
    $\frac{1}{1+x}$
  • $\frac{-1}{(1+x)^2}$
  • D
    कोई नहीं

Answer

Correct option: C.
$\frac{-1}{(1+x)^2}$
(C)

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