Question
यदि ${x^3} + {y^3} - 3axy = 0$, तब $\frac{{dy}}{{dx}} = $
$x$ के सापेक्ष अवकलन करने पर,
$3{x^2} + 3{y^2}.\frac{{dy}}{{dx}} - 3a\left( {x\frac{{dy}}{{dx}} + y} \right) = 0$
$ \Rightarrow $ $3({x^2} - ay) + 3\frac{{dy}}{{dx}}({y^2} - ax) = 0$
$ \Rightarrow $ $\frac{{dy}}{{dx}} = \frac{{ay - {x^2}}}{{{y^2} - ax}}$.
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