MCQ
यदि $x=t+\frac{1}{t}, y=t-\frac{1}{t}$ तो $\frac{d y}{d x}=$
- A$\frac{2 t}{t^2+1}$
- ✓$\frac{t^2+1}{t^2-1}$
- C$\frac{t^2-1}{t^2+1}$
- D$\frac{2 t}{1-t^2}$
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