MCQ
यदि $x=t+\frac{1}{t}, y=t-\frac{1}{t}$ तो $\frac{d y}{d x}=$
  • A
    $\frac{2 t}{t^2+1}$
  • $\frac{t^2+1}{t^2-1}$
  • C
    $\frac{t^2-1}{t^2+1}$
  • D
    $\frac{2 t}{1-t^2}$

Answer

Correct option: B.
$\frac{t^2+1}{t^2-1}$
(B)

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