MCQ
यदि $y=\cot ^{-1}\left(\frac{1-x}{1+x}\right)$ तो $\frac{d y}{d x}=?$
  • A
    $-\frac{1}{1+x^3}$
  • $\frac{1}{1+x^2}$
  • C
    $\frac{1}{\left(1+x^2\right)^{\frac{3}{2}}}$
  • D
    इनमें से कोई नहीं

Answer

Correct option: B.
$\frac{1}{1+x^2}$
B

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