MCQ
यदि $y=\sec \left(\tan ^{-1} x\right)$ हो, तो $\frac{d y}{d x}=$ $x y \quad-x$
- ✓$\frac{x y}{\sqrt{1+x^2}}$
- B$\frac{-x}{\sqrt{1+x^2}}$
- C$\frac{x}{\sqrt{1-x^2}}$
- Dकोई नहीं
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