MCQ
यदि $y=\tan ^{-1} \sqrt{x}$ तो $\frac{-d y}{d x}=$
  • A
    $\frac{1}{2 \sqrt{x(1-x)}}$
  • B
    $\frac{1}{x(1+x)}$
  • C
    $\frac{1}{x^2(1+x)}$
  • $\frac{1}{2 \sqrt{x}(1+x)}$

Answer

Correct option: D.
$\frac{1}{2 \sqrt{x}(1+x)}$
(D)

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