Question
यदि $z = \frac{{7 - i}}{{3 - 4i}}$, तब ${z^{14}} = $
${z^{14}} = {(1 + i)^{14}} = {[{(1 + i)^2}]^7}$= ${(2i)^7} = {2^7}{i^7} = - {2^7}i$.
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$\left[\frac{2^{2020}+1}{2^{2018}+1}\right]+\left[\frac{3^{2020}+1}{3^{2018}+1}\right]+\left[\frac{4^{2020}+1}{4^{2018}+1}\right] +\left[\frac{5^{2020}+1}{5^{2018}+1}\right] + \left[\frac{6^{2020}+1}{6^{2018}+1}\right]$