MCQ
$y{e^{ - x/y}}dx - (x{e^{ - x/y}} + {y^3})dy = 0$ નો ઉકેલ મેળવો.
- ✓$\frac{{{y^2}}}{2} + {e^{ - x/y}} = k$
- B$\frac{{{x^2}}}{2} + {e^{ - x/y}} = k$
- C$\frac{{{x^2}}}{2} + {e^{x/y}} = k$
- D$\frac{{{y^2}}}{2} + {e^{x/y}} = k$
${e^{ - x/y}}(ydx - xdy) = {y^3}dy$ ==> ${e^{ - x/y}}\frac{{(ydx - xdy)}}{{{y^2}}} = ydy$
${e^{ - x/y}}d\left( {\frac{x}{y}} \right) = ydy$.
Integrating both sides, we get
$k - {e^{ - x/y}} = \frac{{{y^2}}}{2}$ ==> $\frac{{{y^2}}}{2} + {e^{ - x/y}} = k$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.