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Molecular Basis of Inheritance — BIOLOGY STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceBIOLOGYMolecular Basis of Inheritance3 Marks
Question
You are repeating the Hershey-Chase experiment and are provided with two isotopes: $^{32}P$ and $^{15}N$ (in place of $^{35}S$ in the original experiment). How do you expect your results to be different?
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Answer

Use of ${ }^{15} \mathrm{N}$ will be inappropriate because method of detection of ${ }^{35} \mathrm{P}$ and ${ }^{15} \mathrm{N}$ is different $\left({ }^{32} \mathrm{P}\right.$ being a radioactive isotope while ${ }^{15} \mathrm{N}$ is not radioactive but is the heavier isotope of nitrogen). Even if ${ }^{15} \mathrm{~N}$ was radioactive then its presence would have been detected both inside the cell ( ${ }^{15} \mathrm{N}$ incorporated as nitrogenous base in DNA) as well as in the supernatant because ${ }^{15} \mathrm{N}$ would also get incorporated in amino group of amino acids in proteins). Hence, the use of ${ }^{15} \mathrm{N}$ would not give any conclusive results.

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