Question
You are repeating the Hershey-Chase experiment and are provided with two isotopes: $^{32}P$ and $^{15}N$ (in place of $^{35}S$ in the original experiment). How do you expect your results to be different?

Answer

Use of ${ }^{15} N$ will be inappropriate because method of detection of ${ }^{35} P$ and ${ }^{15} N$ is different $\left({ }^{32} P\right.$ being a radioactive isotope while ${ }^{15} N$ is not radioactive but is the heavier isotope of nitrogen). Even if ${ }^{15} N$ was radioactive then its presence would have been detected both inside the cell ( ${ }^{15} N$ incorporated as nitrogenous base in DNA) as well as in the supernatant because ${ }^{15} N$ would also get incorporated in amino group of amino acids in proteins). Hence, the use of ${ }^{15} N$ would not give any conclusive results.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free