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M.C.Q [1M]

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12 questions · timed · auto-graded

MCQ 11 Mark
For the reaction A + 3B → 2C + 2D, the concentration of A changes from 0.150 M to 0.0135 M in 1 min. The rate of formation of C in mol/L/s is:
  • A
    5 x 105
  • B
    3 x 10-5
  • 5 x 10-5
  • D
    2.5 x 10-5
Answer
Correct option: C.
5 x 10-5
(c) $5 \times 10^{-5}$
$
\begin{array}{l}
\text { Explanation: rate }=-\frac{d[A]}{d t}=-\frac{1}{3} \frac{d[B]}{d t}=+\frac{1}{2} \frac{d[C]}{d t}=+\frac{1}{2} \frac{d[D]}{d t} \\
\Rightarrow \frac{d[A]}{d t}=-\frac{1}{2} \frac{d[C]}{d t} \\
\Rightarrow \frac{d[C]}{d t}=2 \frac{d[A]}{d t}=-\frac{2 \times(0.0135-0.0150)}{1 \times 60}=5 \times 10^{-5} mol L^{-1} s^{-1} \\
\text { rate }=5 \times 10^{-5} mol L^{-1} s^{-1}
\end{array}
$
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MCQ 21 Mark
The IUPAC name of the compound shown below is:
Image
  • A
    6-bromo-2-chlorocyclohexene
  • 3-bromo-1-chlorocyclohexene
  • C
    2-bromo-6-chlorocyclohex-1-ene
  • D
    1-bromo-3-chlorocyclohexene
Answer
Correct option: B.
3-bromo-1-chlorocyclohexene
(b) 3-bromo-1-chlorocyclohexene
Explanation:Image
IUPAC name: 3-bromo 1-chlorocyclohexene
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MCQ 31 Mark
Amide which gives propanamine by Hoffmann bromamide is:
  • A
    Pentanamide
  • B
    Hexanamide
  • Butanamine
  • D
    Propanamine
Answer
Correct option: C.
Butanamine
(c) Butanamine
Explanation: In the Hoffmann bromamide reaction, the amine formed has one carbon less than that present in the amide. RCONH2 + Br2 + 4NaOH→ RNH2 + Na2CO3 + 2NaBr + 2H2O
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MCQ 41 Mark
For the reaction 3A → 2B, rate of reaction $-\frac{ d [ A ]}{ dt }$ is equal to
  • A
    $\frac{+1}{3} \frac{d[ B ]}{ dt }$
  • B
    $\frac{+2}{3} \frac{d[ B ]}{ dt }$
  • C
    $\frac{+1}{2} \frac{d[ B ]}{ dt }$
  • $\frac{+3}{2} \frac{d[ B ]}{ dt }$
Answer
Correct option: D.
$\frac{+3}{2} \frac{d[ B ]}{ dt }$
(d) $\frac{+3}{2} \frac{d[ B ]}{ dt }$
Explanation: $\frac{+3}{2} \frac{d[ B ]}{ dt }$
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MCQ 51 Mark
Haemoglobin and chlorophyll contain:
  • Fe and Mg
  • B
    Fe and Mn
  • C
    Fe and Co
  • D
    Mg and Fe
Answer
Correct option: A.
Fe and Mg
(a) Fe and Mg
Explanation: Haemoglobin contains Fe and Chlorophyll contains Mg.
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MCQ 61 Mark
The correct IUPAC name ofImage is
  • 2-Methylbutan-2-ol
  • B
    3-Methylbutan-3-ol
  • C
    2,2-Dimethylpropanol
  • D
    tert-butyl alcohol
Answer
Correct option: A.
2-Methylbutan-2-ol
(a) 2-Methylbutan-2-ol
Explanation: The correct IUPAC name of Imageis 2-Methylbutan-2-ol
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MCQ 71 Mark
Cheilosis is caused by deficiency of
  • A
    Vitamin B6
  • Vitamin B2
  • C
    Vitamin C
  • D
    Vitamin B12
Answer
Correct option: B.
Vitamin B2
(b) Vitamin B2
Explanation: Deficiency of Vitamin B2 (Riboflavin) results in Cheilosis (fissuring at corners of mouth and lips).
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MCQ 81 Mark
Ethylidene chloride is a/an __________ .
  • A
    vic-dihalide
  • B
    vinylic halide
  • gem-dihalide
  • D
    allylic halide
Answer
Correct option: C.
gem-dihalide
(c) gem-dihalide
Explanation: Gem-dihalides are dihaloalkanes that have two halogen atoms of the same type attached to the same carbon a in a molecule. The common naming system of gem-dihalides (geminal halide) is alkylidene dihalides. Ethylidene dichloride thus is a gem-dihalide. The chemical formula of ethylidene dichloride is C3H6Cl2.
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MCQ 91 Mark
Lucas reagent is?
  • A
    anhydrous PdCl2 and conc.HCl.
  • B
    anhydrous AlCl3 and conc.HCl.
  • C
    anhydrous CaC2 and conc. HCl.
  • anhydrous ZnCl2 and conc. HCl.
Answer
Correct option: D.
anhydrous ZnCl2 and conc. HCl.
(d) anhydrous ZnCl2 and conc. HCl.
Explanation: "Lucas' reagent" is a solution of anhydrous zinc chloride in concentrated hydrochloric acid.
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MCQ 101 Mark
Match the items of column I with appropriate entries of column II.
Column IColumn II
(а) Кь(i) Elevation in boiling point
(b) Kf(ii) Van't Hoff factor
(c) i(iii) Cryoscopic constant
(d) $\Delta T _{ b }$(iv) Ebullioscopic constant
  • A
    (a) (i), (b) - (ii), (c) - (iii), (d) - (iv)
  • B
    (a) (ii), (b) - (i), (c) - (iii), (d) - (iv)
  • C
    (a) (iii), (b) - (iv), (c) - (i), (d) - (ii)
  • (a) (iv), (b) - (iii), (c) - (ii), (d) - (i)
Answer
Correct option: D.
(a) (iv), (b) - (iii), (c) - (ii), (d) - (i)
(d) (a)-(iv), (b) - (iii), (c) - (ii), (d) - (i)
Explanation: (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
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MCQ 111 Mark
Which of the following reagents would one choose to transform CH3COCI into acetone?
  • A
    CH3MgBr
  • (CH3)2Cd
  • C
    (CH3O)2Mg
  • D
    CH3Cl
Answer
Correct option: B.
(CH3)2Cd
(b) (CH3)2Cd
Explanation: (CH3)2Cd
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MCQ 121 Mark
Image
The structure of A and type of isomerism in the above reaction are respectively.
  • Prop-2-en-2-ol, geometrical isomerism
  • B
    Prop-1-en-2-ol, metamerism
  • C
    Prop-1-en-2-ol, tautomerism
  • D
    Prop-1-en-1-ol, tautomerism
Answer
Correct option: A.
Prop-2-en-2-ol, geometrical isomerism
(a) (c) Prop-1-en-2-ol, tautomerism
Explanation:  ImageProp-1-en-2-ol (A) acetone are tautomers.
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M.C.Q [1M] - Chemistry STD 12 Science Questions - Vidyadip