MATHS M.C.Q. [1 Marks Each]

Since, the coefficient of $x^2$ in $-\frac{5}{3}\text{x}^2\text{y}$ is equal to $-\frac{5}{3}\text{y}$
Hence, the correct alternative is option $(b)$.

$\text { Since, }\left(x^2+2 x-3\right)-\left(-2 x^2+x+1\right)$
$=x^2+2 x-3+2 x^2-x-1$
$=3 x^2+x-4$
So, $-2 x^2+x+1$ is less than $x^2+2 x-3$ by $3 x^2+x-4$
Hence, the correct alternative is option $(b)$.

Since, $2 x^2+1$ has two terms $2 x^2$ and $1$.
So, $2 x^2+1$ is a binomial.
Hence, the correct alternative is option $(a)$.

We have,
$P=3 x^3+3 x^2+3 x+3 \text { and } Q=3 x^2-3 x+3$
Now,
$P-Q\left(3 x^3+3 x^2+3 x+3\right)-\left(3 x^2-3 x+3\right)$
$=3 x^3+3 x^2+3 x+3-3 x^2+3 x-3$
$=3 x^3+6 x$
Hence, the correct alternative is option $(d)$.

As, the coefficient of the term $-\frac43\text{ab}^2$ is $-\frac43,$ the coefficient of the term $\frac14\text{bc}^2$ is $\frac14$ and the coefficient of the term $3ca^2$ is $3$.
So, the product of the coefficients of the terms $=-\frac43\times14\times3=-1$
Hence, the correct alternative is option $(c).$