Question 15 Marks
In the given figure, two straight line $PQ$ and $RS$ intersect at a $O$. If $\angle\text{POS} = 114^\circ, $ find the measure of each of the angles:

$i. \angle\text{POR}$
$ii. \angle\text{ROQ}$
$iii. \angle\text{QOS}$

$i. \angle\text{POR}$
$ii. \angle\text{ROQ}$
$iii. \angle\text{QOS}$
Answer
View full question & answer→$i. \angle\text{POS} +\angle\text{POR} = 180^\circ ($linear pair$)$
$114^\circ + \angle\text{POR}= 180^\circ $
$\angle\text{POR} = 180^\circ -114^\circ = 66^\circ$
$ii.$ Since $\angle\text{POS}$ and $\angle\text{QOR}$ are vertically opposite angles, they are equal.
$\therefore\angle\text{QOR} = 114^\circ$
$iii.$ Since $\angle\text{POR}$ and $\angle\text{QOS}$ are vertically opposite angles, they are equal.
$\therefore\angle\text{QOS} = 66^\circ$

$114^\circ + \angle\text{POR}= 180^\circ $
$\angle\text{POR} = 180^\circ -114^\circ = 66^\circ$
$ii.$ Since $\angle\text{POS}$ and $\angle\text{QOR}$ are vertically opposite angles, they are equal.
$\therefore\angle\text{QOR} = 114^\circ$
$iii.$ Since $\angle\text{POR}$ and $\angle\text{QOS}$ are vertically opposite angles, they are equal.
$\therefore\angle\text{QOS} = 66^\circ$


