Question 11 Mark
Complete the following statements by means of one of those given in brackets against each: If one pair of opposite sides are equal and parallel, then the figure is _____________. (parallelogram, rectangle, trapezium).
Answer
View full question & answer→If one pair of opposite sides are equal and parallel, then the figure is
parallelogram.Explanation:

In $\triangle\text{ABC}$ and $\triangle\text{CDA},$
$AB = DC ($Given$) AC = AC ($Common$)$
$\angle\text{BAC}=\angle\text{DCA} ($Because $AB || CD,$ Alternate interior angle are equal$)$
So, by $SAS$ Congruence rule,
we have $\triangle\text{ABC}\cong\triangle\text{CDA}$
Also, $\angle\text{BCA}=\angle\text{DAC}$ (Corresponding parts of congruent triangles are equal) But,
these are alternate interior angles, which are equal. $AD || BC$
Thus, $AB || CD$ and $AD || BC.$
Hence, quadrilateral $ABCD$ is parallelogram.
parallelogram.Explanation:

In $\triangle\text{ABC}$ and $\triangle\text{CDA},$
$AB = DC ($Given$) AC = AC ($Common$)$
$\angle\text{BAC}=\angle\text{DCA} ($Because $AB || CD,$ Alternate interior angle are equal$)$
So, by $SAS$ Congruence rule,
we have $\triangle\text{ABC}\cong\triangle\text{CDA}$
Also, $\angle\text{BCA}=\angle\text{DAC}$ (Corresponding parts of congruent triangles are equal) But,
these are alternate interior angles, which are equal. $AD || BC$
Thus, $AB || CD$ and $AD || BC.$
Hence, quadrilateral $ABCD$ is parallelogram.

We have, $\angle\text{A}=90^\circ$ In a parallelogram, opposite angles are equal. Therefore, $\angle\text{C}=90^\circ$ Similarly, $\angle\text{A}+\angle\text{D}=180^\circ$ $90^\circ+\angle\text{D}=180^\circ$ $\angle\text{D}=90^\circ$ Also, $\angle\text{B}=90^\circ$ Thus, a parallelogram with all the angles being right angle and opposite sides being equal is a rectangle.

