- AOne of the oxygen atoms has gained electrons.
- BOne of the oxygen atoms has gained two neutrons.
- ✓The two oxygen atoms are isotopes.
- DThe two oxygen atoms are isobars.
50 questions · timed · auto-graded
Valence electrons of an atom are those electrons that are involved in chemical bonding. When forming chemical bonds, atoms may lose, gain, or share valence electrons. An element's chemical properties, including its reactivity, depend on how easily its atoms gain, lose, or share valence electrons.
The first model of an atom was given by $J.J.$ Thomson. According to him, an atom consists of a sphere of positive charge with negatively charged electrons embedded in it.
When alpha particles are sent through a thin metal foil, most of them go straight through the foil because most of the space inside the atom is empty.
Thomson proposed that the nucleus of an atom contains only nucleons.
The particles present in the nucleus of an atom are the proton and the neutron.
Electrons are revolving around the nucleus in circular orbits.
In an atom, the number of electrons is equal to number of protons, which in turn is equal to the atomic number of the element. Also, the sum of number of protons and neutrons represents the mass number of the element.
Chloride ion, $\mathrm{Cl}^{-}$has $18$ electrons so, its electronic configuration is $2, 8, 8.$
It was observed in Rutherford's experiment of gold foil that very few α particles were deflected back by large angles.
The deflection of only a very few α particles helped him to conclude that the nucleus occupies very little space in an atom.
He also concluded that the nucleus would be dense to deflect the α particles by large-angle.
Malleability is a property of metals which can be beaten into sheets.
For his experiment Rutherford needed a very thin sheet of metal and hence he selected gold metal which could be beaten into very thin sheet.
Atomic number = Number of protons $= 3$
Mass number = Number of protons $+$ number of neutrons $=3 + 4 = 7$
Electronic configuration of the atom is $2, 1(K,L)$
Hence, its valency is $1.$
Mass number of the element $=27$
Number of neutrons $=14$
Number of protons $=$ mass number - number of neutrons
$= 27 - 14 = 13$
As the ion of this element has $3$ positive charges, it means that it has lost $3$ electrons. Therefore, there are now $10$ electrons in the ion.