MCQ 11 Mark
Statement-1 (A): The area of a segment of a circle formed by a chord of length 4 cm subtending an angle of $90^{\circ}$ at the centre is $(2 \pi+4) cm ^2$.
Statement-2 (R): The area of a segment of a circle formed by a chord of length 2 a subtending an angle of $90^{\circ}$ at the centre is $(\pi-2) \frac{a^2}{2}$ sq. units.

Statement-2 (R): The area of a segment of a circle formed by a chord of length 2 a subtending an angle of $90^{\circ}$ at the centre is $(\pi-2) \frac{a^2}{2}$ sq. units.

- AStatement-1 and Statement-2 are True; Statement-2 is a correct explanation for Statement-1.
- BStatement-1 and Statement-2 are True; Statement-2 is not a correct explanation for Statement-1.
- CStatement-1 is True, Statement-2 is False.
- ✓Statement-1 is False, Statement- 2 is True.
Answer
View full question & answer→Correct option: D.
Statement-1 is False, Statement- 2 is True.
(D)
$\triangle O A B$ is a right triangle right angled at $O$.
$
O A^2+O B^2=A B^2 \Rightarrow 2 r^2=A B^2 \Rightarrow r=\frac{A B}{\sqrt{2}}=\sqrt{2} a
$
Area of segment $A C B=\frac{90}{360} \times \pi r^2-\frac{1}{2} r^2=\frac{\pi}{4} r^2-\frac{1}{2} r^2=\left(\frac{\pi-2}{4}\right) r^2=(\pi-2) \frac{a^2}{2}$
So, statement-2 is true.
Replacing $2 a$ by 4 i.e. $a$ by 2 , we obtain
Area of the segment $A C B=(\pi-2) \times \frac{2^2}{2} cm^2=(2 \pi-4) cm ^2$
So, statement-1 is not true. Hence, option (d) is correct.
$\triangle O A B$ is a right triangle right angled at $O$.
$
O A^2+O B^2=A B^2 \Rightarrow 2 r^2=A B^2 \Rightarrow r=\frac{A B}{\sqrt{2}}=\sqrt{2} a
$
Area of segment $A C B=\frac{90}{360} \times \pi r^2-\frac{1}{2} r^2=\frac{\pi}{4} r^2-\frac{1}{2} r^2=\left(\frac{\pi-2}{4}\right) r^2=(\pi-2) \frac{a^2}{2}$
So, statement-2 is true.
Replacing $2 a$ by 4 i.e. $a$ by 2 , we obtain
Area of the segment $A C B=(\pi-2) \times \frac{2^2}{2} cm^2=(2 \pi-4) cm ^2$
So, statement-1 is not true. Hence, option (d) is correct.