50 questions · timed · auto-graded




$\ \ \ \ \ \ \ \ \ \ \ \text{H}_2 \\ \ \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \text{H}_3\text{C} {-} \text{C} {-} \text{OH}$
On adding conc. sulphuric acid to ethanol to ethanol and heating the mixture up to 443 k (443 K - 273 = 170º C) gives ethene.
$\text{C}_2\text{H}_5\text{OH} \xrightarrow[170^\circ]{\text{Conc H}_2\text{SO}_4} \text{CH}_2 = \text{CH}_2 +\text{H}_2 \\$
The role of conc. H2SO4 in the above reaction is that it is used as a dehydrating agent and causes dehydration of ethanol.
| Name | General Formula |
| Alkene | CnH2n |
| Alkyne | CnH2n-2 |
Chemical equation involved is:
$\text{CH}_2=\text{CH}_2+\text{H}_2\xrightarrow{\text{Ni or Pt}}\text{CH}_3-\text{CH}_3$
The reactant is Ethene and the product formed is Ethane.Take two strips of blue litmus paper. Place a drop each of the alcohol and carboxylic acid on these strips separately. The blue litmus paper turns red in the case of carboxylic acid and remains unaffected in the case of alcohol.
A pinch of sodium hydrogen carbonate or sodium carbonate is added, to both separately. If brisk effervescence with the evolution of a colourless gas is observed, it indicates the presence of carboxylic acid.
If no change is observed then it confirms the presence of the alcohol.
$ \ \ \ \ \ \ \text{H} \ \ \ \text{H} \ \ \ \text{H} \ \ \ \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} {-} \text{C} {-} \text{C} {-} \text{C} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \text{H} \ \ \ \text{H} \ \ \ \text{H} \ \ \ \ \text{H} \\ \ \ \ \ \ \ \ \ \ \text{n}-\text{butane}$
$ \ \ \ \ \ \ \text{H} \ \ \ \ \ \ \ \ \ \text{H} \ \ \ \ \ \ \ \ \ \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} \ \ \ {-} \ \ \ \text{C} \ \ \ {-} \ \ \ \text{C} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \text{H}\ \ \ \text{H} {-} \text{C} {-} \text{H} \ \ \ \text{H} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{H} \\ 2-\text{Methyl propane}$
$\text{C}_2\text{H}_5\text{OH}+\text{3O}_2\xrightarrow{\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }}\text{2CO}_2+\text{3H}_2\text{O}$
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow[\Delta443\text{K}]{\text{Conc.}\text{H}_2\text{SO}_4}\text{c}_2\text{H}_4+\text{H}_2\text{O}$
$2\text{C}_2\text{H}_5\text{OH}+\text{2Na}\xrightarrow{\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }}\text{2C}_2\text{H}_5\text{ONa}+\text{H}_2$.
$\text{CH}_3\text{COOH}+\text{C}_2\text{H}_5\xrightarrow{\text{ }\text{Conc.}\text{H}_2\text{SO}}{\text{ }}\text{CH}_3\text{COOC}_2\text{H}_5+\text{H}_2\text{O}$
Activity-Chemical equation:
2Na + 2C2H5OH → 2C2H5ONa + H2 Product formed: sodium ethaoxide When X is heated with excess conc. sulphuric acid dehydration reaction takes place. Ethanol is converted to ethene (C2H4).$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ O} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{||} \\ \text{CH}_3 {-} \text{CH}_2 {-} \text{C} {-} \text{H} \\ \ \ \ \ \ \ \ \ \text{Propanal}$ $\ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \text{CH}_3 {-} \text{C}=\text{O} \\ \ \ \ \text{Propanone}$
$\ \ \ \ \ \ \ \ \ \ \ \ \text{H} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|} \\ \text{H} {-}\text{C} {=}\text{C} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \text{H}$
The first member of alkynes is ethyne and its structure is given below.$\text{H - C}\equiv\text{C - H}$
Ethyne burns in air with a sooty flame due to incomplete combustion caused by limited supply of air.

But ethyne burns in oxygen with a clean flame with temperature 30000C because of complete combustion.
This oxy-acetylene flame is used for welding.
Such a high temperature cannot be achieved without mixing oxygen. Therefore, mixture of ethyne and air is not used for welding.
$\text{CH}_{3}\text{-CHO} \text{ and CH}_{3}-\text{CH}_{2}-\text{CHO}$
In $\text{CH}_{3}-\text{CHO}$ compound, $\text{-CHO}$ part and in $\text{CH}_{3}-\text{CH}_{2}\text{-CHO, -CH}_{2}\text{-CHO}$ part will determine their physical and chemical properties.Alkanes | Alkenes |
An alkane is hydrocarbon in which the carbon atoms are connected by only single covalent bond. | An alkane is an unsaturated hydrocarbon in which the two carbon atoms are connected by a double bond. |
General formula of alkane is $\text{C}_{\text{n}}\text{H}_{2\text{n + 2.}}$ | General formula of $\text{C}_{\text{n}}\text{H}_{2\text{n}}.$ |
The simplest alkane is methane $\text{(CH}_{4}).$ | The simplest alkene is ethene $\text{(C}_{2}\text{H}_{4}).$ |
![]() | ![]() |
Alkanes generally burn in air with a blue and non-sooty flame. | Alkenes burn in air with a yellow and sooty flame. |
Alkanes undergo substitution reactions. | Alkenes undergo reactions. |
Alkanes do not decolourise red-brown colour of bromine water. | Alkenes decolourise the bromine water. |
$\text{C}_{2}\text{H}_{4}\text{O}_{2} + \text{Alcohol}\xrightarrow{\text{H}_{2}\text{SO}_{4}}\text{ 'X'}$
$\text{Alcohol}\xrightarrow[\text{Alkaline KMnO}_{4}]{\text{Oxidation}}\text{C}_{2}\text{H}_{4}\text{O}_{2}$
Name: $\text{CH}_{3}\text{COOH} \text{ (Ethanoic Acid)}$
Structure: $\ \ \ \ \ \ \text{H}\\ \ \ \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} {-} \text{C} {-} \text{O} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{||} \\ \ \ \ \ \ \ {\text{H}}\ \ \ \text{ O}$
Name: $\text{CH}_{3} - \text{CH}_{2}-\text{OH} \text{ (Ethanol)}$
Structure: $\ \ \ \ \ \ \text{H} \ \ \ \text{H}\\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{|}\\ \text{H} {-} \text{C} {-} \text{C} {-} \text{O} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|}\ \ \ \ \ \text{|} \\ {\ \ \ \ \ \ \text{H}} \ \ \ \ \text{H} $
Name: $\text{CH}_{3}\text{COOC}_{2}\text{H}_{5} \text{ (Ethyl ethanoate)}$
Structure: $ \ \ \ \ \ \ \text{H} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ H}\ \ \ \ \text{H } \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} {-} \text{C} {-} \text{O} {-} \text{C} {-}\text{C} {-}\text{H} \\ \ \ \ \ \ \ \text{ |}\ \ \ \ \ \text{||}\ \ \ \ \ \ \ \ \ \ \text{|}\ \ \ \ \ \text{|} \\ \ \ \ \ \ {\text{ H}} \ \ \ \ \text{O} \ \ \ \ \ \ \ \ \text{H} \ \ \ \text{H}$
Chemical reactions:
$\underset{\substack{\text { Corboxylic acid } \\ \text { (Ethanoic acid) }}}{ CH _3 COOH }+\underset{\text { Alcohol (Ethanol) }}{ CH _3 CH _2 OH } \xrightarrow{ H _2 SO _4} \underset{( X ) \text { (Ethyl ethanoate) }}{ CH _3 COOC _2 H _5}$
$\underset{\text { Ethanol }}{ CH _3 CH _2 OH } \xrightarrow[\text { alkaline } KMnO _4]{ o } \underset{\text { Ethanoic acid }}{ CH _3 COOH }+ H _2 O$
of these compounds.
Esters in the presence of an acid or a base, give back alcohol and carboxylic acid as per the following reaction of the ester in the presence of sodium hydroxide solution. $CH _3 COOC _2 H _5 \xrightarrow{ NaOH } \underset{\text { Ethanol }}{ C _2 H _5 OH }+\underset{\text { Ethanoic acid }}{ CH _3 COOH }$
| Esterification | Saponification |
| Carboxylic acid reacts with acohols in the presence of a little conc. sulphuric acid to from esters. | On treating an ester with a converted back to alcohol and sodium salt of carboxylic acid. |
Example:Ethanoic acid reacts with ethanol in the presence of a little conc. sulphuric acid to form exters. $C_2H_5OH+CH_3COOH\xrightarrow { \text { Cons.} {H_2SO_4}}CH_3COOC_2H_5+H_2O$ | Example:Ethyl ethanoate on reaction with sodium hydroxide gives ethanol and sodium ethanoate. $CH_3COOC_2H_5+NaOH\xrightarrow { }C_2H_5OH+CH_3COONa$ |


Hydrocarbons are defined as the compounds which are composed of Hydrogen and Carbon atoms. The names and general formula for saturated Hydrocarbons is Alkane and the formula is: CnH2n+2. The 'n' represents number of carbon atoms in molecule of the alkane. The names and general formula for unsaturated hydrocarbons are:
Alkene and Alkyne. The general formula for alkene is: CnH2n and for Alkyne, it is: CnH2n-2
Structure of saturated hydrocarbon:
Molecular formula for 1 carbon atom = CH4
Structure:
$\ \ \ \ \ \ \text{H} \\ \ \ \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} {-} \text{H} \\ \ \ \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \text{H}$
Structure of unsaturated hydrocarbon:
Molecular formula for 2 carbon atom is Ethene C2H4
The structure of Ethene is as follows:

Molecular formula for 2 carbon atom is Ethyne C2H2.
The chemical equation for the reaction involved:
CH3COOH + CH3CH2OH → CH3COOC2H5 + H2O. (Include H2SO4 as a catalyst) CH3COOH = Ethanoic acid. CH3CH2OH = Ethanol. CH3COOC2H5 = Ethyl Acetate. When esters (CH3COOC2H5) with sodium hydroxide (NaOH) forms sodium ethanoate (CH3COONa) as the main product and ethanol (C2H5OH). CH3COOC2H5 + NaOH → CH3COONa + C2H5OH + heat. This reaction is known as Saponification Reaction, Alkaline Hydrolysis or Esters Hydrolysis. This reaction is used in the production of soap and hence the name is Saponification Reaction. It is an exothermic reaction since heat is evolved.Define the term functional group. Identify the functional group present in
$\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }{\text{O}}\\ \text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\parallel\\ \text{H}\text{ }- \text{C}\text{ }-\text{H}\text{ }$
$\ \ \ \ \ \ \ \ \text{H}\ \ \ \ \ \text{OH} \\ \ \ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \ \ \text{|} \\ \text{H}-\text{C}-\text{C}=\text{O}\\ \ \ \ \ \ \ \ \ \ \text{|} \\ \ \ \ \ \ \ \ \ \text{H}$
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow[443\text{K}]{\text{H}_2\text{SO}_3}\text{CH}_2 = \text{CH}_2$
Role of conc. H2SO4: It acts as dehydrating agent as it allows the removal of H2O from ethanol.$ \underset{\text { Ethanoic acid }}{CH _3 COOH} + \underset{\text { Ethanol}}{C_2H_5OH} \xrightarrow{ conc.H_2SO_4 } \underset{\text { Ethyl ethanoate}}{ CH_3COOC_2H_5 }+H_2O$
Electronic configuration of A = 2, 8, 7
Since it has '7' electrons in its outermost shell.
So, group to which A belongs = 10 + 7 = group 17.
Period to which element A belongs = no. of shells = 3
So, period to which A belongs is 3rd
Atomic no. of B = 19
Electronic configuration of A = 2, 8, 8, 1
Since it has 'l' electrons in its outermost shell.
So, group to which B belongs = group 1.
Period to which element B belongs = no. of shells = 4
So, period to which B belongs is 4th
Since, Valency of A = -1
Valency of B = +1

So, when A combines with B, the formula will be BA.

The bond formed between B and A is an ionic bond.
$ \underset{\text { Propanol }}{CH _3 -CH_2- CH_2-OH} \xrightarrow[\text { or, Acdiffed } K _2 Cr _2 O _7+\text { Heat }]{\text { Alkaline } KMnO _4+\text { Heat }}\underset{\text { Propanoic acid}}{ CH_3-CH_2-COOH }$
| Soaps | Detergents |
| Soap molecules are sodium or potassium salts of long-chain carboxylic acids. | Detergent molecules are ammonium or sulphonate salts of long-chain carboxylic acids |
| They form scum upon reaction with calcium and magnesium ions present in hard water. | They do not form insoluble precipitates with calcium and magnesium ions. |
Cleansing action of soaps: The oily spot present on clothes is organic in nature and insoluble in water. Therefore, it cannot be removed by only washing with water. When soap is dissolved in water, its hydrophobic ends attach themselves to the oily spot and remove it from the cloth. Then, the molecules of soap arrange themselves in the form of micelle and trap the dirt at the centre of the cluster. These micelles remain suspended in the water. Hence, the oily spots are easily rinsed away by water.

| Compound | Functional Group |
| Alcohol | -OH |
| Aldehyde | -CHO |
| Ketone | >C=O |
| Carboxylic acid | -COOH |

Compound | Functional Group | Structure |
Ethanol | Hydroxy (-OH) | $CH_3CH_2OH$ |
Ethanoic acid | Carboxylic acid (-COOH) | $CH_3COOH$ |
The product formed is:

$\text{H}_{2}\text{SO}_{4}$ is a dehydrating agent. So, ethanol undergoes dehydration i.e., loses a water molecule to form ethane.
Homologous series of carbon compounds are so called because in such a series of compounds, the same functional group dictates the properties of the carbon compound regardless of the length of the carbon chain. The two consecutive members of a homologous series are $\text{CH}_{3}\text{OH and} \text{ C}_{2}\text{H}_{5}\text{OH.}$
