If the potential difference between the end of a wire of fixed resistance is doubled, by how much does the electric power increase?
Answer
$\text{P}=\frac{\text{V}_2}{\text{R}}$ R is fixed. V becomes double. Now, $\text{P}=\frac{(2\text{V})2}{\text{R}}=\frac{4\text{V}_2}{\text{R}}$ So, the electric power becomes four times its previous value.
How do you think the brightness of two lamps arranged in parallel compares with the brightness of two lamps arranged in series (both arrangements having one cell)?
Answer
The brightness of two lamps arranged in parallel is much more those arranged in series.
Explain why, filament type electric bulbs are not power efficient.
Answer
Filament type electric bulbs are not power efficien because most of the electric power consumed by the filament of a bulb appears as heat and only a small amount of electric power is converted into light.
Draw a circuit diagram showing two electric lamps connected in parallel together with a cell and a switch that works both lamps. Mark an on your diagram to show where an ammeter should be placed to measure the current.
An electrician has wired a house in such a way that if a lamp gets fused in one room of the house, all the lamps in other rooms of the house stop working. What is the defect in the wiring?