Question 12 Marks
In the given circuit, find:
a. Total resistance of the network of resistors
b. Current through ammeter A, and
c. Potential difference across $3 \Omega$ and $6 \Omega$ resistors
a. Total resistance of the network of resistors
b. Current through ammeter A, and
c. Potential difference across $3 \Omega$ and $6 \Omega$ resistors
Answer
View full question & answer→a. $\mathrm{X}_{1}=3 \Omega ; \mathrm{X}_{2}=3 \Omega$
$\frac{1}{x_{2}}=\frac{1}{6}+\frac{1}{6}=\frac{2}{6}=\frac{1}{3}$
Total resistance $\mathrm{R}=\mathrm{X}_{1}+\mathrm{X}_{2}=3 \Omega+3 \Omega=6 \Omega$
b. Current through ammeter A, $I=\frac{V}{R}=\frac{6 V}{6 \Omega}=1 \mathrm{~A}$
c. Potential difference across $3 \Omega=1 \mathrm{~A} \times 3 \Omega=3 \mathrm{~V}$
Potential difference across $6 \Omega=\frac{1}{2} \mathrm{~A} \times 6 \Omega=3 \mathrm{~V}$
$\frac{1}{x_{2}}=\frac{1}{6}+\frac{1}{6}=\frac{2}{6}=\frac{1}{3}$
Total resistance $\mathrm{R}=\mathrm{X}_{1}+\mathrm{X}_{2}=3 \Omega+3 \Omega=6 \Omega$
b. Current through ammeter A, $I=\frac{V}{R}=\frac{6 V}{6 \Omega}=1 \mathrm{~A}$
c. Potential difference across $3 \Omega=1 \mathrm{~A} \times 3 \Omega=3 \mathrm{~V}$
Potential difference across $6 \Omega=\frac{1}{2} \mathrm{~A} \times 6 \Omega=3 \mathrm{~V}$
