Question 12 Marks
A student uses spectacles of focal length $-2.5 m.$
$i.$ Name the defect of vision he is suffering from.
$ii.$ Which lens is used for the correction of this defect?
$iii.$ List two main causes of developing this defect.
$iv.$ Compute the power of this lens.
$i.$ Name the defect of vision he is suffering from.
$ii.$ Which lens is used for the correction of this defect?
$iii.$ List two main causes of developing this defect.
$iv.$ Compute the power of this lens.
Answer
View full question & answer→$f = -2.5 m$
$i.$ Since the focal length is negative, it is a concave lens and it is used in myopia.
$ii.$ Concave
$iii.$ excessive curvature of the cornea.
$ii.$ elongation of the eyeball.
$iv. f = -2.5 m$
The negative sign of focal length indicates that the lens used is concave hence the boy is suffering from myopia $($short$-$sightedness$).$
Power of the lens $=\frac{1}{f(i n m)}$
$=\frac{1}{(-2.5)}$
$=-2.5 D $
$i.$ Since the focal length is negative, it is a concave lens and it is used in myopia.
$ii.$ Concave
$iii.$ excessive curvature of the cornea.
$ii.$ elongation of the eyeball.
$iv. f = -2.5 m$
The negative sign of focal length indicates that the lens used is concave hence the boy is suffering from myopia $($short$-$sightedness$).$
Power of the lens $=\frac{1}{f(i n m)}$
$=\frac{1}{(-2.5)}$
$=-2.5 D $