Question 13 Marks
The arithmetic mean of 1, 3, 5, 6, X and 10 is 6, then find the value of X.
Answer
View full question & answer→In this question, mean is given as 6 .
The observations are $1,3,5,6, X$ and 10 . So the total no. of observations is 6 . One observation is missing which we take as X .
Mean $=$ Total of all observations $/$ No. of observations
$\begin{array}{l}
\bar{X}=\frac{\Sigma X}{n} \\
\bar{X}=\frac{1+3+5+6+X+10}{6} \\
\Rightarrow \quad 6=\frac{25+X}{6} \Rightarrow 36=25+X \\
\therefore X=36-25=11
\end{array}$
The observations are $1,3,5,6, X$ and 10 . So the total no. of observations is 6 . One observation is missing which we take as X .
Mean $=$ Total of all observations $/$ No. of observations
$\begin{array}{l}
\bar{X}=\frac{\Sigma X}{n} \\
\bar{X}=\frac{1+3+5+6+X+10}{6} \\
\Rightarrow \quad 6=\frac{25+X}{6} \Rightarrow 36=25+X \\
\therefore X=36-25=11
\end{array}$