Question 16 Marks
Find out the missing value of the variate for the following distribution whose mean is 31.87.
| Value (X) | 12 | 20 | 27 | 33 | ? | 54 |
| Frequency (f) | 8 | 16 | 48 | 90 | 30 | 8 |
Answer
View full question & answer→The missing value of the variate is taken as Y.
Here,
$\begin{array}{l}
\bar{X}=31.87 \text { (Given) } \\
\Sigma f=200 \\
\Sigma f X=5114+30 Y
\end{array}$
Now,
$\bar{X}=\frac{\Sigma f X}{\Sigma f}$
Now substituting the values in above formula, we get
$\begin{array}{l}
\Rightarrow \quad 31.87=\frac{5114+30 Y}{200} \\
\Rightarrow 31.87 \times 200=5114+30 Y \\
\Rightarrow 6374=5114+30 Y \\
\Rightarrow 1260=30 Y \\
\Rightarrow Y=\frac{1260}{30}=42
\end{array}$
Hence, the missing value of the variate for the given distribution is $4 2$.
| Value (X) | Frequency (f) | fX |
| 12 | 8 | 96 |
| 20 | 16 | 320 |
| 27 | 48 | 1296 |
| 33 | 90 | 2970 |
| Y | 30 | 30Y |
| 54 | 8 | 432 |
| $\Sigma f=200$ | $\Sigma f X=5114+30 Y$ |
$\begin{array}{l}
\bar{X}=31.87 \text { (Given) } \\
\Sigma f=200 \\
\Sigma f X=5114+30 Y
\end{array}$
Now,
$\bar{X}=\frac{\Sigma f X}{\Sigma f}$
Now substituting the values in above formula, we get
$\begin{array}{l}
\Rightarrow \quad 31.87=\frac{5114+30 Y}{200} \\
\Rightarrow 31.87 \times 200=5114+30 Y \\
\Rightarrow 6374=5114+30 Y \\
\Rightarrow 1260=30 Y \\
\Rightarrow Y=\frac{1260}{30}=42
\end{array}$
Hence, the missing value of the variate for the given distribution is $4 2$.
