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16 questions · timed · auto-graded

MCQ 11 Mark
The radius of the circle is 3 times the radius of another circle, the circumference of the new circle will be how many times the circumference of the smaller circle?
  • 3 times
  • B
    $\frac{1}{3}$ times
  • C
    6 times
  • D
    9 times
Answer
Correct option: A.
3 times
(A) 3 times
Explanation : Let the radius of smaller circle be $r$.
Then, its circumference $=2 \pi r$
$
\begin{aligned}
\text { New radius } & =3 r \\
\text { New circumference } & =2 \pi(3 r)=6 \pi r \\
& =3 \times 2 \pi r \\
& =3 \times \text { (smaller circumference })
\end{aligned}
$
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MCQ 21 Mark
If three sides of a triangle are $6 cm, 8 cm, 10 cm$, then the altitude of the triangle using the largest side as base will be
  • A
    8 cm
  • B
    6 cm
  • 4.8 cm
  • D
    4.4 cm
Answer
Correct option: C.
4.8 cm
(C) 4.8 cm
Explanation : Area of $\triangle A B C=\frac{1}{2} \times A B \times B C$
Image
$\begin{array}{rlrl} \text { Also, } & \text { area of } \triangle A B C & =\frac{1}{2} \times A C \times B P \\ \therefore & \frac{1}{2} \times 8 \times 6 & =\frac{1}{2} \times 10 \times B P \\ \Rightarrow & B P & =\frac{8 \times 6}{10}=4.8 cm\end{array}$
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MCQ 31 Mark
The perimeter of a rhombus is 40 m and its height is 5 m . Its area is
  • A
    60 sq. m
  • 50 sq . m
  • C
    45 sq. m
  • D
    55 sq.m.
Answer
Correct option: B.
50 sq . m
(B) 50 sq . m
Explanation :
$
\begin{array}{l}
\text {  The side of the rhombus }=\frac{\text { perimeter }}{4} \\
=\frac{40}{4}=10 m \\
\therefore \quad \text { Area of rhombus }=10 \times 5=50 \text { sq. } m .
\end{array}
$
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MCQ 41 Mark
The length of a room is 5.5 m and width is 3.75 m . Find the cost of paving the floor by slabs at the rate of ₹ 800 per sq. metre
  • A
    ₹ 15,000
  • B
    ₹ 15,500
  • C
    ₹ 15,600
  • ₹ 16,500
Answer
Correct option: D.
₹ 16,500
(D) ₹ 16,500
Explanation :
$\begin{aligned} \text {  Area of floor } & =(5.5 \times 3.75) m ^2 \\ & =20.625 m^2 \\ \therefore \quad \text { Cost of paving } & =₹ (800 \times 20.625) \\ & = ₹ 16,500 .\end{aligned}$
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MCQ 51 Mark
Which of the following trains is the fastest ?
  • A
    $25 m / sec$
  • B
    $1500 m / min$
  • C
    $90 km / hr$
  • None of these
Answer
Correct option: D.
None of these
(D) None of these
Explanation :
$
\begin{aligned}
25 m / sec & =\left(25 \times \frac{18}{5}\right) km / hr \\
& =90 km / hr
\end{aligned}
$
and
$
\begin{aligned}
25 m / sec & =(25 \times 60) m / min \\
& =1500 m / min
\end{aligned}
$
So, all the three speeds are equal.
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MCQ 61 Mark
A car moves at speed of $80 km / hr$. What is the speed of the car in metres per second?
  • A
    $8 m / sec$
  • B
    $20 \frac{1}{9} m / sec$
  • $22 \frac{2}{9} m / sec$
  • D
    None of these
Answer
Correct option: C.
$22 \frac{2}{9} m / sec$
(C) $22 \frac{2}{9} m / sec$
$
\text { Explanation : Speed }=\left(80 \times \frac{5}{18}\right) m / sec
$
$\begin{aligned}= & \frac{200}{9} m / sec =22 \frac{2}{9} m / sec \\ & {\left[\because 1 km / hr =\frac{5}{18} m / sec \right] }\end{aligned}$
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MCQ 71 Mark
'A' does a work in 10 days and 'B' does the same work in 15 days. In how many days they together will do the same work ?
  • A
    5 days
  • 6 days
  • C
    8 days
  • D
    9 days
Answer
Correct option: B.
6 days
(B) 6 days
$
\begin{aligned}
\text { Explanation : A's } 1 \text { day's work } & =\frac{1}{10} \\
\text { B's } 1 \text { day's work } & =\frac{1}{15} \\
\therefore \quad(A+B) \text { 's } 1 \text { day's work } & =\frac{1}{10}+\frac{1}{15}=\frac{1}{6}
\end{aligned}
$
So, both together will finish the work in 6 days.
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MCQ 81 Mark
A man can do a piece of work in 5 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone ?
  • A
    $6 \frac{1}{2}$ days
  • B
    7 days
  • $7 \frac{1}{2}$ days
  • D
    8 days
Answer
Correct option: C.
$7 \frac{1}{2}$ days
(C) $7 \frac{1}{2}$ days
Explanation: Son's 1 day's work $=\left(\frac{1}{3}-\frac{1}{5}\right)=\frac{2}{15}$
$\therefore$ The son alone can do the work in$
\frac{15}{2}=7 \frac{1}{2} \text { days }
$
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MCQ 91 Mark
A clock is started at noon. By 10 minutes past 5 , the hour hand has turned through
  • A
    $145^{\circ}$
  • B
    $150^{\circ}$
  • $155^{\circ}$
  • D
    $160^{\circ}$
Answer
Correct option: C.
$155^{\circ}$
(C) $155^{\circ}$
Explanation : Angle traced by hour hand in 12 hrs
$
=360^{\circ}
$
Angle traced by hour hand in 5 hrs 10 min . i.e., $\frac{31}{6} hrs$
$
\begin{array}{l}
=\left(\frac{360}{12} \times \frac{31}{6}\right)^0 \\
=155^{\circ}
\end{array}
$
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MCQ 101 Mark
On $8^{\text {th }}$ Dec, 2007 Saturday falls. What day of the week was it on $8^{\text {th }}$ Dec. 2006 ?
  • A
    Sunday
  • B
    Thursday
  • C
    Tuesday
  • Friday
Answer
Correct option: D.
Friday
(D) Friday
Explanation : The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on $8^{\text {th }}$ Dec, 2007 will be 1 day beyond the day on 8 Dec, 2006.
But, $8^{\text {th }}$ Dec, 2007 is Saturday
$\therefore 8^{\text {th }}$ Dec, 2006 is Friday.
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MCQ 111 Mark
January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009.
  • A
    Monday
  • B
    Wednesday
  • Thursday
  • D
    Sunday
Answer
Correct option: C.
Thursday
(C) Thursday
Explanation : The year 2008 is a leap year. So, it has 2 odd days.
$1^{\text {st }}$ day of the year 2008 is Tuesday. (Given)
So, $1^{\text {st }}$ day of the year 2009 is 2 days beyound Tuesday
Hence, it will be Thursday.
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MCQ 121 Mark
January 1,2007 was Monday. What day of the week lies on January 1, 2008 ?
  • A
    Monday
  • Tuesday
  • C
    Wednesday
  • D
    Sunday
Answer
Correct option: B.
Tuesday
(B) Tuesday
Explanation : The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2008 will be 1 day beyound Monday.
Hence, it will be Tuesday.
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MCQ 131 Mark
The average of first five multiples of 3 is
  • A
    3
  • 9
  • C
    12
  • D
    15
Answer
Correct option: B.
9
(B) 9
Explanation : The five multiples of 3 are :
3, 6, 9, 12, 15
$
\therefore \text { Average }=\frac{3+6+9+12+15}{5}=\frac{45}{5}=9
$
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MCQ 141 Mark
The average of 20 numbers is zero. Of them, at most, how many may be greater than zero?
  • A
    $0$
  • B
    1
  • C
    10
  • 19
Answer
Correct option: D.
19
(D) 19
$
\begin{aligned}
\text { Explanation : Average of } 20 \text { numbers } & =0 \\
\therefore \quad \text { Sum of } 20 \text { numbers } & =(0 \times 20) \\
& =0
\end{aligned}
$
It is quite possible that 19 of these numbers may be positive and if their sum is $a$, then 20 th number is $(-a)$.
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MCQ 151 Mark
The average of all the numbers between 6 and 34, which are divisible by 5 is
  • A
    18
  • 20
  • C
    24
  • D
    30
Answer
Correct option: B.
20
(B) 20
Explanation : The numbers between 6 and 34, which are divisible by 5 are $10,15,20,25,30$.
$
\therefore \quad \text { Average }=\frac{10+15+20+25+30}{5}=\frac{100}{5}=20
$
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MCQ 161 Mark
David obtained 76, 65, 8267 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
  • 75
  • B
    96
  • C
    72
  • D
    76
Answer
Correct option: A.
75
(A) 75
$\begin{aligned} \text { Explanation : Average } & =\frac{76+65+82+67+85}{5} \\ & =\frac{375}{5}=75\end{aligned}$
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MCQ - Applied Maths STD 11 Science Questions - Vidyadip