Question types

Binomial Theorem question types

211 questions across 7 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

211
Questions
7
Question groups
5
Question types
Sample Questions

Binomial Theorem questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Value of $\sum^{\infty}_{\text{k}=1}\sum^{\text{k}}_{\text{r}=0}\frac{1}{3^{\text{k}}}\big({^\text{k}}\text{C}_{\text{r}}\big)$ is:
  • $2$
  • B
    $\frac{2}{3}$
  • C
    $\frac{1}{3}$
  • D
    $\text{None of these}$

Answer: A.

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If the $r^{th}$ term in the expansion of $\Big(\frac{\text{x}}{3}-\frac{2}{\text{x}^{2}}\Big)^{10}$ contains $x^4$, then $r$ is equal to:
  • $2$
  • B
    $3$
  • C
    $4$
  • D
    $5$

Answer: A.

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The number of integral terms in the expansion of $\Big(3^{\frac{1}{8}}+5^{\frac{1}{4}}\Big)^{1024}$ is:
  • A
    $512$
  • B
    $256$
  • C
    $128$
  • $129$

Answer: D.

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The $4^{th}$ term in the expansion of $\Big(\sqrt{\text{x}}+\frac{1}{\text{x}}\Big)^{12}$ is:
  • A
    $110\text{x}^{\frac{3}{2}}$
  • $220\text{x}^{\frac{3}{2}}$
  • C
    $220\text{x}^{2}$
  • D
    $110\text{x}^{2}$

Answer: B.

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State which of the statement in True or False.
The sum of coefficients of the two middle terms in the expansion of $(1 + x)^{2n - 1}$ is equal to $^{2n - 1}C_n.$
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State which of the statement in True or False.
The expression $79 + 97$ is divisible by $64.$
Hint: $79 + 97 = (1 + 8)^7 - (1 – 8)^9$​​​​​​​​​​​​​​
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Q 213 Marks Question3 Marks
Find n, if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of ${\left( {\sqrt[4] 2 + \frac{1}{{\sqrt [4]{3} }}} \right)^n}$ is $\sqrt 6 :1$.
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Fill in the blank.
The coefficient of $a^{-6}b^4$ in the expansion of $\Big(\frac{1}{\text{a}}-\frac{2\text{b}}{3}\Big)^{10}$ is ___________.
[Hint: $\text{T}_5=\ ^{10}\text{C}_4\Big(\frac{1}{\text{a}}\Big)^\text{b}\Big(\frac{-2\text{b}}{3}\Big)^4=\frac{1120}{27}\text{a}^{-6}\text{b}^4]$
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Fill in the blank.
If the seventh terms from the beginning and the end in the expansion of $\Big(3\sqrt{2}+\frac{1}{3\sqrt{3}}\Big)^\text{n}$ are equal, then n equals _____________.
[Hint: $\text{T}_7=\text{T}_{\text{n}-7+2}\Rightarrow\ ^\text{n}\text{C}_6\Big(2^\frac{1}{3}\Big)^{\text{n}-6}\bigg(\frac{1}{3^\frac{1}{3}}\bigg)^6$ $=\ ^\text{n}\text{C}_{\text{n}-6}\Big(2^\frac{1}{3}\Big)^6\bigg(\frac{1}{3^\frac{1}{3}}\bigg)^{\text{n}-6}$
$\Rightarrow\Big(2^\frac{1}{3}\Big)^{\text{n}-12}=\bigg(\frac{1}{3^{\frac{1}{3}}}\bigg)^{\text{n}-12}\Rightarrow$ only problem when $\text{n}-12=0\Rightarrow\text{n}=12]$
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