Question 11 Mark
If the mid-points of the sides of a triangle AB; BC; CA are D(1, 2, -3), E(3, 0, 1) and F(-1, 1, -4), then the centriod of the triangle ABC is ________.
Answer
View full question & answer→If the mid-points of the sides of a triangle AB; BC; CA are D(1, 2, -3), E(3, 0, 1) and F(-1, 1, -4), then the centriod of the triangle ABC is (1, 1, -2).
Solution:
Given that, mid-points of sides of AABC are D(1, 2, -3), E(3, 0, 1) and F(-1, 1, -4).
Now, from the geometry of centroid, we know that the centroid of $\triangle\text{DEF}$ is same as the centroid of $\triangle\text{ABC}.$
$\therefore$ Centroid of $\triangle\text{ABC}\equiv\text{G}\Big(\frac{1+3-1}{3},\frac{2+0+1}{3},\frac{"-3+1-4}{3}\Big)\equiv\text{G}(1,1,-2)$
Solution:
Given that, mid-points of sides of AABC are D(1, 2, -3), E(3, 0, 1) and F(-1, 1, -4).
Now, from the geometry of centroid, we know that the centroid of $\triangle\text{DEF}$ is same as the centroid of $\triangle\text{ABC}.$
$\therefore$ Centroid of $\triangle\text{ABC}\equiv\text{G}\Big(\frac{1+3-1}{3},\frac{2+0+1}{3},\frac{"-3+1-4}{3}\Big)\equiv\text{G}(1,1,-2)$
