1 Marks Question

Question 11 Mark

Numbers 1 to 10 are written on 10 tickets. A ticket is drawn randomly. Find the probability of the number written on it to be a multiple of 3.

Answer

$S=\{1,2,3,4,5,6, \ldots 10\}, n(S)=10$
Number of favourable outcomes
$\begin{aligned}= & \{3,6,9\}, n(E)=3 \end{aligned}$
$\text {Required probability}=\frac{n( E )}{n(S)}=\frac{3}{10}$

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Question 21 Mark

A card is drawn from a pack of 52 playing cards. Find the probability of its being a jack card.

Answer

$\begin{aligned} \text { Favourable outcomes } & =4 \\ \text { Total outcomes } & =52 \\ \text { Required probability } & =\frac{4}{52}=\frac{1}{13}\end{aligned}$

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Question 31 Mark

Out of 1000 ships going in the sea, 100 are sink. Find the probability of sinking of any ship going in the sea.

Answer

$\begin{aligned}\text {Here,}\quad P ( A ) & =\frac{m}{n} \\ m & =100, n=1,000 \\ P ( A ) & =\frac{m}{n}=\frac{100}{1000}=\frac{1}{10}\end{aligned}$

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Question 41 Mark

Find the probability of getting an even number on throwing of a dice.

Answer

$\begin{aligned}\text { Favourable outcomes } & =(2,4,6)=3 \\\text { Total outcomes } & =6 \\\text { Required probability } & =\frac{3}{6}=\frac{1}{2}\end{aligned}$

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Question 51 Mark

A coin is tossed twice. Write the probability of obtaining head on both tosses.

Answer

$\text { Probability }=\frac{1}{4}$

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Question 61 Mark

What is the probability of 6 Sundays in a month of 31 days?

Answer

In a month of 31 days, there will be 4 weeks and 3 days. Occurrence of 4 Sundays in a month is a sure event and there can be 5 Sundays in the month if on any of the remaining three days, Sunday falls. But it is impossible to have 6 Sundays in the month. Hence, probability of 6 Sundays in the month is 0.

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Question 71 Mark

Calculate the probability of one Sunday in a week.

Answer

There is always one Sunday in a week. Hence it is a sure event. The required probability is 1.

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Question 81 Mark

The probability of two horses $A$ and $B$ of winning in a horse race is $\frac{1}{3}$ and $\frac{2}{5}$ respectively. On which horse would you like to bet?

Answer

$\because \quad P ( A )=\frac{1}{3}=\frac{5}{15}, \quad P ( B )=\frac{2}{5}=\frac{6}{15}$
$\Rightarrow \quad P ( A )< P ( B )$.
Hence, the probability of winning of horse $B$ is more, so I would like to bet on horse $B.$

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