The centre of the conic represented by the equation $2{x^2} - 72xy + 23{y^2} - 4x - 28y - 48 = 0$ is
- A$\left( {\frac{{11}}{{15}},\;\frac{2}{{25}}} \right)$
- B$\left( {\frac{2}{{25}},\;\frac{{11}}{{25}}} \right)$
- C$\left( {\frac{{11}}{{15}},\; - \frac{2}{{25}}} \right)$
- ✓$\left( { - \frac{{11}}{{25}},\; - \frac{2}{{25}}} \right)$
Answer: D.
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