Let $\mathrm{P}(\mathrm{x}, \mathrm{y}, \mathrm{z})$ be a point in the first octant, whose projection in the xy-plane is the point $\mathrm{Q}$. Let $\mathrm{OP}=\gamma$; the angle between $OQ$ and the positive $\mathrm{x}$-axis be $\theta$; and the angle between $\mathrm{OP}$ and the positive $\mathrm{z}$-axis be $\phi$, where $\mathrm{O}$ is the origin. Then the distance of $\mathrm{P}$ from the $\mathrm{x}$-axis is :
- ✓$\gamma \sqrt{1-\sin ^2 \phi \cos ^2 \theta}$
- B$\gamma \sqrt{1+\cos ^2 \theta \sin ^2 \phi}$
- C$\gamma \sqrt{1-\sin ^2 \theta \cos ^2 \phi}$
- D$\gamma \sqrt{1+\cos ^2 \phi \sin ^2 \theta}$
Answer: A.
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