(D) $\frac{1}{x^{2}}$ $0<x<1$ between $0$ and $1, x^2<x<1$ $\frac{1}{x^2}>\frac{1}{x}>1$, also $1>x>0$ (given) therefore, $\frac{1}{x^2}>\frac{1}{x}>1>x>0$ thus, $\frac{1}{x^2}$ is greatest. Hence, option d is the correct answer
If B > A, then which expression will have the highest value, given that A and B are positive integers:
A
A - B
B
A $\times$ B
C
A + B
✓
can't say
Answer
Correct option: D.
can't say
(D) can't say As, B > A $\Rightarrow$ A < B $\Rightarrow$ A – B < 0 A + B > 0 and AB >0 If A = 1, B = 4 then, AB < A+B If A = 2, B = 4 then, AB > A+B Thus, we can’t say which one of A+B and AB has higher value. Hence, option d is the correct answer