1,041 questions across 1 question group — pick any mix to generate a Chemistry paper with step-by-step answer keys.
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Answer: A.
View full solution →|
List $I$ (Conversion) |
List $II$ (Number of Faraday required) |
| $A$. $1 \mathrm{~mol}$ of $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$ | $l$. $3 \mathrm{~F}$ |
| $B$. $1 \mathrm{~mol}$ of $\mathrm{MnO}_4^{-}$to $\mathrm{Mn}^{2+}$ | $II$. $2 F$ |
| $C$. $1.5 \mathrm{~mol}$ of $\mathrm{Ca}$ from molten $\mathrm{CaCl}_2$ | $III$. $1F$ |
| $D$. $1 \mathrm{~mol}$ of $\mathrm{FeO}$ to $\mathrm{Fe}_2 \mathrm{O}_3$ | $IV$. $5 \mathrm{~F}$ |
Choose the correct answer from the options given below:
Answer: D.
View full solution →Answer: D.
View full solution →$Ni ( s )+2 Ag ^{+}(0.001 M ) \rightarrow Ni ^{2+}(0.001 M )+2 Ag ( s )$
$($ Given that $E _{\text {cell }}^{\circ}=10.5 \,V , \frac{2.303 RT }{ F }=0.059$ at $298\, K )$
Answer: B.
View full solution →$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O$,
$E^{o} _{ Mn ^{2+} / MnO _{4}^{-}}=-1.510 \,V$
$\frac{1}{2} O _{2}+2 H ^{+}+2 e ^{-} \rightarrow H _{2} O$,
$E _{ O _{2} / H _{2} O }^{o}=+1.223 \,V$
Will the permanganate ion, $MnO _{4}^{-}$liberate $O _{2}$ from water in the presence of an acid ?
Answer: D.
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