Download App

Chemistry 2 Marks Questions

Amines · CBSE STD 12 Science (CBSE - English Medium). 12 questions.

Questions

2 Marks Questions

Take a timed test

12 questions · self-marked practice — reveal the answer and mark yourself.

Question 12 Marks
Compound (A) is formed when benzene diazonium chloride is mixed with KI solution. Compound (B) is formed when ( A ) reacts with sodium in the presence of dry ether. Write the names of (A) and (B) and the equations of the chemical reactions involved.
Answer
br>Image
View full question & answer→
Question 22 Marks
Compound (A) is formed when aniline is treated with $NaNO _2+ HCl$ at 273-278 K. Compound (B) is formed when cuprous chloride is added to (A).
Write the name of compound (A) and (B) and the equations of the chemical reactions involved.
View full question & answer→
Question 42 Marks
Explain isocyanide test for primary amines.
Answer
When aliphatic and aromatic primary amine, is heated with chloroform and alcoholic (ethanolic) KOH, it forms foul smelling substance carbylamine or isocyanide. This is called isocyanide test.
Secondary and tertiary amines do not give this test.Therefore, this reaction is used in testing primary amines.
Image
View full question & answer→
Question 52 Marks
How will you make the following changes?
(i) Methyl alcohol to ethyl amine.
(ii) Ethanoic acid to ethanamine.
View full question & answer→
Question 62 Marks
Two isomeric compounds $(A$ and $B)$ have $C _4 H _{11} N$ molecular formula react with $HNO _2$ and forms compounds $(C)$ and $(D). C$ is hardly oxidised but it reacts immediately with Lucas reagent whereas $D$ reacts with Lucas reagent in $5$ minutes and it also gives haloform reaction. Identify $A, B, C$ and $D$.
Answer

Image
$A$ and $B$ are primary amines, which react $HNO_2$ and forms corresponding alcohols, $C$ is a tertiary alcohol which is hardly oxidised and it reacts immediately with Lucas reagent and $D$ is a secondary alcohols, hence it reacts with Lucas reagent in $5$ minutes and due toImagegroup it gives haloform reaction.
View full question & answer→
Question 72 Marks
Of all the methods of preparing amines identify by which aniline cannot be prepared?
Answer
Aniline cannot be prepared by the following methods:
(i) Reduction of nitriles
(ii) Reduction of amides
(iii) Reduction of oximes
(iv) Reductive amination of carbonyl compounds.
View full question & answer→
Question 92 Marks
How is $p-$nitroaniline is prepared by nitration of aniline? Explain with equations.
Answer
Due to the oxidising properties of conc. $HNO_3$ present in the nitration mixture, it oxidises aniline. Therefore, to control this reaction, the $-NH_2$ group is protected by acetylation of aniline before nitration.
Image
View full question & answer→
Question 102 Marks
Ethyl amine is basic while acetamide is ampheteric. Explain the reason.
Answer
In ethylamine, the lone electron pair of Nitrogen of $-NH_2$ group is easily available to accept proton. Whereas in acetamide due to the presence of Imagegroup and its $-I$ effect the lone electron pair of $-NH_2$ group is involved in resonance hence, it is not readily available to accept proton. There by, ethyl amine is basic whereas acetamide is amphoteric in nature.
Image
View full question & answer→
Question 112 Marks
(i) Name the product obtained when excess of ethanol is treated with ammonia in the presence of Alumina?
(ii) How is methyl amine prepared from the following compounds? Give the equation.
(a) $CH _3- MgCl$
(b) $CH _3 COCl$
Answer
(i) When excess of ethanol is treated with ammonia in the presence of alumina, a mixture of primary, secondary and tertiary amines is obtained
Image
View full question & answer→
Generate Paper FreeAll Amines topics