STD 12 - 7.1 inderfinite integral - CBSE STD 12 Science Mathematics Questions - Vidyadip

Question types

STD 12 - 7.1 inderfinite integral question types

565 questions across 1 question group — pick any mix to generate a Mathematics paper with step-by-step answer keys.

565

Questions

1

Question groups

5

Question types

M.C.Q (1 Marks)

Sample Questions

STD 12 - 7.1 inderfinite integral questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1M.C.Q (1 Marks)1 Mark

$\int_{}^{} {\frac{{dx}}{{\tan x + \cot x}}} = $

A
$\frac{{\cos 2x}}{4} + c$
B
$\frac{{\sin 2x}}{4} + c$
C
$ - \frac{{\sin 2x}}{4} + c$
✓
$ - \frac{{\cos 2x}}{4} + c$

Answer: D.

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Q 2M.C.Q (1 Marks)1 Mark

$\int_{}^{} {\frac{{dx}}{{\sqrt x + \sqrt {x - 2} }} = } $

✓
$\frac{1}{3}[{x^{3/2}} - {(x - 2)^{3/2}}] + c$
B
$\frac{2}{3}[{x^{3/2}} - {(x - 2)^{3/2}}] + c$
C
$\frac{1}{3}[{(x - 2)^{3/2}} - {x^{3/2}}] + c$
D
$\frac{2}{3}[{(x - 2)^{3/2}} - {x^{3/2}}] + c$

Answer: A.

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Q 3M.C.Q (1 Marks)1 Mark

If $\int_{}^{} {(\sin 2x - \cos 2x)} \;dx = \frac{1}{{\sqrt 2 }}\sin (2x - a) + b$, then

A
$a = \frac{\pi }{4},\;b = 0$
B
$a = - \frac{\pi }{4},\;b = 0$
C
$a = \frac{{5\pi }}{4},\;b = $any constant
✓
$a = - \frac{{5\pi }}{4},\;b = $any constant

Answer: D.

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Q 4M.C.Q (1 Marks)1 Mark

$\int_{}^{} {\left( {1 + x + \frac{{{x^2}}}{{2\;!}} + \frac{{{x^3}}}{{3\;!}} + ..........} \right)\;dx = } $

A
$ - {e^x} + c$
✓
${e^x} + c$
C
${e^{ - x}} + c$
D
$ - {e^{ - x}} + c$

Answer: B.

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Q 5M.C.Q (1 Marks)1 Mark

$\int_{}^{} {{{(\sec x + \tan x)}^2}dx = } $

✓
$2(\sec x + \tan x) - x + c$
B
$1/3{(\sec x + \tan x)^3} + c$
C
$\sec x(\sec x + \tan x) + c$
D
$2(\sec x + \tan x) + c$

Answer: A.

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