7. Alternating current Physics - 7. Alternating current

A $10 \mu \mathrm{F}$ capacitor is connected to a $210 \mathrm{~V}, 50 \mathrm{~Hz}$ source as shown in figure. The peak current in the circuit is nearly $(\pi=3.14)$ :

• ✓
  $0.93 \mathrm{~A}$
• B
  $1.20 \mathrm{~A}$
• C
  $0.35 \mathrm{~A}$
• D
  $0.58 \mathrm{~A}$

Answer: A.

The net impedance of circuit (as shown in figure) will be $...........\,\Omega$

• A
  $15$
• B
  $10 \sqrt{2}$
• C
  $25$
• ✓
  $5 \sqrt{5}$

Answer: D.

• ✓
  $1.59\,kHz$
• B
  $15.9\,rad / s$
• C
  $15.9\,kHz$
• D
  $1.59\,rad / s$

Answer: A.

• A
  $6.28\,\Omega$, zero
• B
  $6.28\,\Omega$, infinity
• ✓
  $0.628\,\Omega$, zero
• D
  $0.628\,\Omega$, infinity

Answer: C.

• ✓
  $0.707$
• B
  $1$
• C
  $1.414$
• D
  $2$

Answer: A.