2 Marks Questions

Question 12 Marks

Find the simple interest, when: Principal $= Rs. 1200$, Rate of Interest $= 18\%$ per annum, and Time $= 4$ month.

Answer

Principal $(P) = Rs. 1200,$
Rate of interest $(R) = 18\% p.a.$,
Time $(T) = 4$ month $\text{T}=\frac{4}{12}=\frac{1}{3}\ \text{year}$
$\Big(\because 1\text{ month} =\frac{1}{12}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{1200\ \times\ 18\ \times\ \frac{1}{3}}{100}$
$=\frac{1200\ \times\ 18\ \times\ 1}{100\ \times\ 3}$
$=\text{Rs. }720$

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Question 22 Marks

Find the simple interest, when: Principal $= Rs. 2000,$ Rate of Interest $= 5\%$ per annum, and Time $= 5$ years.

Answer

Principal $(P) = Rs. 2000$,
Rate of interest $(R) = 5\% p.a$.,
Time $(T) = 5$ years
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{2000\ \times\ 5\ \times\ 5}{100}$ $=\text{Rs. }500$

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Question 32 Marks

Find the simple interest, when:
Principal $= Rs. 4500$, Rate of Interest $= 4\%$ per annum, and Time $= 6$ month.

Answer

Principal $(P) = Rs. 4500$,
Rate of interest $(R) = 4% p.a$.,
Time $(T) = 6$ month
$\text{T}=\frac{6}{12}=\frac{1}{2}\ \text{year}$ $\Big(\because 1\text{ month} =\frac{1}{12}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{4500\ \times\ 4\ \times\ \frac{1}{2}}{100}$
$=\frac{4500\ \times\ 4\ \times\ 1}{100\ \times\ 2}$
$=\text{Rs. }90$

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Question 42 Marks

Find the simple interest, when: Principal $= Rs. 500$, Rate of Interest $= 12.5%$ per annum, and Time $= 4$ years.

Answer

Principal $= Rs. 500$, Rate of Interest $= 12.5\%$ per annum, and Time $= 4$ years.
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{500\ \times\ 12.5\ \times\ 4}{100}$
$=\text{Rs. }250$

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Question 52 Marks

Find the simple interest, when: Principal $= Rs. 1000$, Rate of Interest $= 10\%$ per annum, and Time $= 73$ days.

Answer

Principal $= Rs. 1000$, Rate of Interest $= 10\%$ per annum, and Time $= 73$ days $\text{T}=\frac{73}{365}\ \text{year}$
$\Big(\because 1\text{ day} =\frac{1}{365}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{1000\ \times\ 10\ \times\ \frac{73}{365}}{100}$
$=\frac{1200\ \times\ 18\ \times\ 73}{100\ \times\ 365}$
$=\text{Rs. }20$

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Question 62 Marks

Find the simple interest, when:
Principal = ₹ 1000, $\quad$ Rate of Interest = 10% per annum $\quad$ and Time = 73 months.

Answer

$₹ 20$

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Question 72 Marks

Find the simple interest, when:
Principal = ₹ 12000, $\quad$ Rate of Interest = 18% per annum $\quad$ and Time = 4 months.

Answer

$₹ 720$

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Question 82 Marks

Find the simple interest, when:
Principal = ₹ 4500, $\quad$ Rate of Interest = 4% per annum $\quad$ and Time = 6 months.

Answer

$₹ 90$

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Question 92 Marks

Find the simple interest, when:
Principal = ₹ 500, $\quad$ Rate of Interest = 12.5% per annum $\quad$ and Time = 4 years.

Answer

$₹ 250$

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Question 102 Marks

Find the simple interest, when:
Principal = ₹ 2000, $\quad$ Rate of Interest = 5% per annum $\quad$ and Time = 5 years.

Answer

$₹ 500$

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