1 Marks Question

Question 11 Mark

Write $‘T’$ for true and $‘F’$ for false for the following: Simple interest on $Rs. 1000$ at $5\%$ per annum for $73$ days is $Rs. 10$.

Answer

True.
$P = Rs. 1000$
$R = 5\%$
$T = 73$ days
$=\frac{73}{365}\text{ days}$
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$=\frac{1000\times5\times73}{100\times365}$
$=\text{Rs. }10$

View full question & answer→

Question 21 Mark

Fill in the blanks: $AT$ simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$ The rate of interest is (......)% per annum.

Answer

$AT$ simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$
The rate of interest is $8\%$ per annum.
Let the sum be $Rs. x$
Amount $=\text{Rs. }\frac65\text{x}$
$\text{S.I.}=\text{A}-\text{P}$
$=\frac{6}{5}\text{x}-\text{x}$
$=\text{Rs. }\frac{\text{x}}{5}$
Let the rate of interest be $R \%$
Time $= 2.5$ years
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\frac{\text{x}}{5}=\frac{\text{x}\times\text{R}\times\text{2.5}}{100}$
$\Rightarrow\text{R}=\frac{100}{2.5\times5}$
$\Rightarrow8$

View full question & answer→

Question 31 Mark

Write $‘T’$ for true and $‘F’$ for false for the following:
A sum doubles itself at simple interest at $10\%$ per annum in $10$ years.

Answer

True.
Let the sum be $Rs. x$
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\text{S.I.}=\frac{\text{x}\times10\times10}{100}$
$\text{S.I.}=\text{Rs. x}$
Amount $= S.I. + P$
$= x + x$
$= Rs. 2x$

View full question & answer→

Question 41 Mark

Fill in the blanks: $\text{R}=\frac{100\times\text{S.I.}}{(.......)\times\text{T}}$

Answer

$\text{R}=\frac{100\times\text{S.I.}}{(\text{P})\times\text{T}}$

View full question & answer→

Question 51 Mark

Fill in the blanks: $AT (....)\%$ per annum simple interest a sum doubles itself in $10$ years.

Answer

AT $10\%$ per annum simple interest a sum doubles itself in $10$ years.
Let the amount be $Rs. x$ Amount $= Rs. 2x\ S.I. = A - P = 2x - x = Rs. x$
Let the rate of interest be $R \%$ Time $= 10$ years $\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$ $\Rightarrow\text{x}=\frac{\text{x}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\text{R}=\frac{100}{10}$ $\Rightarrow\text{R}=10\%$

View full question & answer→

Question 61 Mark

Fill in the blanks: $\text{P}=\frac{100\times(......)}{\text{R}\times\text{T}}$

Answer

$\text{P}=\frac{100\times\text{S.I.}}{\text{R}\times\text{T}}$

View full question & answer→

Question 71 Mark

Write $‘T’$ for true and $‘F’$ for false for the following:
Simple interest on $Rs. x$ for $x$ years is $Rs. x.$ Then, the rate of interest is $x\ \%$ per annum.

Answer

False.
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\text{x}=\frac{\text{x}\times\text{R}\times\text{x}}{100}$
$\Rightarrow\text{R}=\frac{100\times\text{x}}{\text{x}\times\text{x}}$
$\Rightarrow\text{R}=\frac{100}{\text{x}}\%$

View full question & answer→

Question 81 Mark

Write $‘T’$ for true and $‘F’$ for false for the following: $\text{Rate}=\frac{100\times\text{S.I.}}{\text{P}\times\text{T}}$

Answer

True.

View full question & answer→

Maths 1 Marks Question

Test yourself on this topic