MCQ 1511 Mark
The price of a watch including $8 \%$ $VAT$ is Rs. $810$. What is its basic price?
- A
Rs. $675$
- B
Rs. $729$
- ✓
Rs. $750$
- D
Rs. $745$
AnswerCorrect option: C. Rs. $750$
Let the original price be Rs. $x$.
$VAT = 8 \%$ of Rs. $x$
$=\text{Rs. }\Big(\text{x}\times\frac{8}{100}\Big)$
$=\text{Rs. }\frac{8\text{x}}{100}$
$\therefore$ Price including $VAT$ $=\text{Rs. }\Big(\text{x}+\frac{8\text{x}}{100}\Big)$
$=\text{Rs. }\frac{108\text{x}}{100}$
Now, $\frac{108\text{x}}{10}=810$
$\Rightarrow\text{x}=\Big(810\times\frac{100}{108}\Big)$
$\Rightarrow\text{x}=750$
View full question & answer→MCQ 1521 Mark
The percentage of ratio $2 : 3$ is:
- ✓
$66.66 \%$
- B
$44.44 \%$
- C
$55.55 \%$
- D
AnswerCorrect option: A. $66.66 \%$
$2 : 3=\frac{2}{3}$
Converting into percentage, we have to multiply the ration by $100$.
$\frac{2}{3}\times100\%=\frac{200}{3}=66.66\%$
View full question & answer→MCQ 1531 Mark
Tick $(\checkmark)$ the correct answer in the following: ? $ \%$ of $400 = 60.$
Answer$\frac{\text{x}}{100}\times400=60$
$\Rightarrow400\text{x}=6000$
$\Rightarrow\text{x}=15$
View full question & answer→MCQ 1541 Mark
What should be the rate of interest per annum if interest is calculated quarterly?
AnswerIf we will calculate interest quarterly, the rate of interest will be divided by one fourth.
For example,
If your annual interest rate $= 8 \%$
Divide $8$ by $4$ to find that the quarterly interest rate is $2$ percent.
I.e., $8 \times \frac{1}{4} = \frac{8}{4} = 2\%$
View full question & answer→MCQ 1551 Mark
There are $50$ students in a class of which $40$ are boys and the rest are girls. The ratio of the number of boys and number of girls is:
- A
$2 : 3$
- B
$1 : 5$
- ✓
$4 : 1$
- D
$2 : 5$
AnswerCorrect option: C. $4 : 1$
Number of Girls $= 50 - 40 = 10$
Required ratio $= 40 : 10 = 4 : 1$
View full question & answer→MCQ 1561 Mark
On selling a chair for Rs. $680$, a man loses $15 \%$. To gain $15 \%$, it must be sold for:
- A
Rs. $800$
- B
Rs. $860$
- ✓
Rs. $920$
- D
Rs. $884$
AnswerCorrect option: C. Rs. $920$
$SP =$ Rs. $680$
Loss percentage $= 15 \%$
Now, $\text{CP}=\Big\{\frac{100}{(100-\text{loss}\%)}\times\text{SP}\Big\}$
$=\text{Rs. }\Big\{\frac{100}{(100-15)}\times680\Big\}$
$\text{Rs. }\Big(\frac{100}{85}\times680\Big)$
$=\text{Rs. }800$
$\therefore\text{Desired SP}=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{CP}\Big\}$
$=\text{Rs. }\Big\{\frac{(100+15)}{100}\times800\Big\}$
$=\text{Rs. }\Big(\frac{115}{100}\times800\Big)$
$=\text{Rs. }920$
View full question & answer→MCQ 1571 Mark
Tick $(\checkmark)$ the correct answer in the following:
Ravi buys some toffees at $5$ for a rupee and sells them at $2$ for a rupee. His gain percent is:
- A
$30 \%$
- B
$40 \%$
- C
$50\%$
- ✓
$150\%$
AnswerCorrect option: D. $150\%$
$L.C.M$ of $5$ and $2 = (5 \times 1 \times 2) = 10$
Let $10$ be the number of toffees bought
$CP$ of $5$ toffees = Rs. $1$
$CP$ of $1$ toffee $=\text{Rs. }\Big(\frac{1}{5}\Big)$
$\therefore$ $CP$ of $10$ toffees $=\text{Rs.}\Big(\frac{1}{5}\times10\Big)=\text{Rs. }2$
$SP$ of $2$ toffees = Rs. $1$
$SP$ of $1$ toffees $=\text{Rs.}\Big(\frac{1}{2}\Big)$
$\therefore$ $SP$ pf $10$ toffees $=\text{Rs.}\Big(\frac{1}{2}\times10\Big)=\text{Rs. }5$
Gain = Rs. $(5 - 2)$ = Rs. $3$
Gain percentage $\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{3}{2}\times100\Big)=150\%$
View full question & answer→MCQ 1581 Mark
If $x \%$ is the discount per cent on a marked price $y$, then selling price is:
- A
$\frac{\text{x}}{100}\text{y}$
- ✓
$\text{y}-\frac{\text{x}}{100}\text{y}$
- C
$\text{y}+\frac{\text{x}}{100}\text{y}$
- D
$\frac{100}{\text{x}\times\text{y}}$
AnswerCorrect option: B. $\text{y}-\frac{\text{x}}{100}\text{y}$
We know that discount $=\frac{\text{Discount%}}{100}\times\text{marked price}$
$\Rightarrow\text{Discount} =\frac{\text{x}}{100}\times\text{y}$
Selling price = Marked price - Discount
$\Rightarrow \text{selling price}=\text{y}-\frac{\text{x}}{100}\times\text{y}$
View full question & answer→MCQ 1591 Mark
The $C.I.$ on a certain sum for $2$ years is Rs. $410$ and $S.I.$ is Rs. $400$. What is the rate of interest per annum?
- A
$10 \%$
- B
$8 \%$
- ✓
$5 \%$
- D
$4 \%$
AnswerCorrect option: C. $5 \%$
$5 \%$
View full question & answer→MCQ 1601 Mark
Tick $(\checkmark)$ the correct answer in the following: The value of a machine depreciates at the rate of $20 \%$ per annum. It was purchased $2$ years ago. If its present value is Rs. $40000$, for how much was it purchased?
- A
Rs. $56000$
- ✓
Rs. $62500$
- C
Rs. $65200$
- D
Rs. $56500$
AnswerCorrect option: B. Rs. $62500$
Principal value = Rs. $40000$
Rate of depreciation $(R) = 20\%$ $p.a$
Value of machine $2$ years ago
$=\text{A}\div\Big(1-\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }40000\div\Big(1-\frac{20}{100}\Big)^2$
$=\text{Rs. }40000\div\Big(\frac{4}{5}\Big)^2$
$=\text{Rs. }40000\times\frac{5}{4}\times\frac{5}{4}$
$=\text{Rs. }62500$
View full question & answer→MCQ 1611 Mark
The ratio $4 : 25$ converted to percentage is:
- A
$8 \%$
- B
$4 \%$
- ✓
$16 \%$
- D
$25 \%$
AnswerCorrect option: C. $16 \%$
$16 \%$
View full question & answer→MCQ 1621 Mark
If the difference between $81$ and $Cl$ on a certain sum of money for $3$ years at $10 \%$ $p.a.$ is Rs. $15.50$. The sum is:
- A
Rs. $2000$
- ✓
Rs. $1000$
- C
Rs. $500$
- D
Rs. $1500$
AnswerCorrect option: B. Rs. $1000$
Rs. $1000$
View full question & answer→MCQ 1631 Mark
If $90 \%$ of $x$ is $315\ km$, then the value of $x$ is:
- A
$325\ km$
- ✓
$350\ km$
- C
$350\ m$
- D
$325\ m$
AnswerCorrect option: B. $350\ km$
We have $90 \%$ of $x = 315\ Km$
$\frac{90}{100}\times\text{x}=315$
$\text{x}=\frac{315\times100}{90}=\frac{315\times10}{9}=350$
$x = 350\ km$
Hence, option $(b)$ is correct.
View full question & answer→MCQ 1641 Mark
Convert the fraction$\frac{1}{2}$ into a percentage.
- A
$25\%$
- B
$8\%$
- ✓
$12.5\%$
- D
$16\%$
AnswerCorrect option: C. $12.5\%$
Multiply the given fraction by $100$ to get the percentage value.
$\frac{1}{2}\times100=12.5\%$
View full question & answer→MCQ 1651 Mark
A sum is taken for two years at $16\% p.a$. If interest is compounded after every three months, the number of times for which interest is charged in $2$ years is:
AnswerSince, rate of interest is calculated after every three months.
Similarly, the time period for amount in a year will $4$ times.
If amount is taken for $2$ yr, means $4 \times 2 = 8$ times charged in $2$ yr.
Hence, option $(a)$ is correct
View full question & answer→MCQ 1661 Mark
A bag is available for Rs. $90$. The shopkeeper allows $10 \%$ discount on the marked price. What is the marked price of the bag?
- ✓
Rs. $100$
- B
Rs. $90$
- C
Rs. $110$
- D
Rs. $10$
AnswerCorrect option: A. Rs. $100$
$100 - 10 = 90$
If the bag is available for Rs. $90$, then marked price = Rs. $100$
View full question & answer→MCQ 1671 Mark
In selling a plot of land for Rs. $61200$, a profit of $20 \%$ is made. The cost price of the plot is:
- ✓
Rs. $51000$
- B
Rs. $50000$
- C
Rs. $49000$
- D
Rs. $52000$
AnswerCorrect option: A. Rs. $51000$
$\because$ If $S.P.$ is Rs. $120 (100 + 20)$
$C.P.$ = Rs. $100$
$\therefore$ If $S.P.$ is Rs. $61200$
$C.P.$ $=\frac{100}{120}\times61200=\text{Rs. }51000$
View full question & answer→MCQ 1681 Mark
Tick $(\checkmark)$ the correct answer in the following: The sum that amounts to Rs. $4913$ in $3$ years at $6\frac{1}{4}\%$ per annum compounded annually, is.
- A
Rs. $3096$
- B
Rs. $4076$
- C
Rs. $4085$
- ✓
Rs. $4096$
AnswerCorrect option: D. Rs. $4096$
Amount = Rs. $4913$
Rate (R) $=6\frac{1}{4}=\frac{25}{4}\%$
Period $(n) = 3$ years
$\therefore \text{A}=\text{P}\div\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=4913\div\Big(1\frac{25}{4\times100}\Big)^3$
$=\text{Rs. }4913\div\Big(1\div\frac{1}{16}\Big)^3$
$=4913\div\Big(\frac{17}{16}\Big)^3$
$=4913\times\frac{16}{17}\times\frac{16}{17}\times\frac{16}{17}$
$=\text{Rs. }4096$
$\therefore\text{Sum}=\text{Rs. }4096$
View full question & answer→MCQ 1691 Mark
The ratio of 10km per hour to $30\ km$ per hour is:
- A
$3 : 1$
- B
$1 : 2$
- ✓
$1 : 3$
- D
$2 : 1$
AnswerCorrect option: C. $1 : 3$
$1 : 3$
View full question & answer→MCQ 1701 Mark
Tick $(\checkmark)$ the correct answer in the following: In an examination, Nitin gets $98$ marks. This amounts to $56 \%$ of the maximum marks. What are the maximum marks?
Answer$\therefore\frac{56\text{x}}{100}=98$
$\Rightarrow56\text{x}=9800$
$\Rightarrow\text{x}=175$
View full question & answer→MCQ 1711 Mark
Tick $(\checkmark)$ the correct answer in the following: A bookseller sells a book for Rs. $100,$ gaining Rs. $20$. His gain percent is:
- A
$20 \%$
- ✓
$25 \%$
- C
$22 \%$
- D
AnswerCorrect option: B. $25 \%$
$CP = SP =$ Rs. $(100 - 20)$ = Rs. $80$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{20}{80}\times100\Big)\%$
$=25\%$
View full question & answer→MCQ 1721 Mark
Tick $(\checkmark)$ the correct answer in the following: Oranges are bought at $5$ for Rs. $10$ and sold at $6$ for Rs. $15$. His gain percent is:
- A
$50\%$
- B
$40\%$
- C
$35\%$
- ✓
$25\%$
AnswerCorrect option: D. $25\%$
$L.C.M$ of $5$ and $2 = (5 \times 1 \times 6) = 30$
Let $30$ be the number of oranges bought
$CP$ of $5$ oranges = Rs. $10$
$CP$ of $1$ oranges $=\text{Rs. }\Big(\frac{10}{5}\Big)\text{Rs. }2$
$\therefore$ $CP$ of $30$ oranges Rs. $(2 \times 30) =$ Rs. $60$
$SP$ of $6$ oranges = Rs. $15$
$SP$ of $1$ oranges $=\text{Rs. }\Big(\frac{15}{6}\Big)$
$\therefore$ $SP$ pf $30$ oranges $=\text{Rs.}\Big(\frac{15}{6}\times30\Big)=\text{Rs. }75$
Now, Gain = Rs. $(75 - 60)$ = Rs. $15$
$\therefore$ Gain percentage $\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{15}{60}\times100\Big)=25\%$
View full question & answer→MCQ 1731 Mark
For calculation of interest compounded half yearly, keeping the principal same, which one of the following is true.
- A
Double the given annual rate and half the given number of years.
- B
Double the given annual rate as well as the given number of years.
- C
Half the given annual rate as well as the given number of years.
- ✓
Half the given annual rate and double the given number of years.
AnswerCorrect option: D. Half the given annual rate and double the given number of years.
If interest is compounded half-yearly, then $\text{R}=\frac{\text{R}}{2}$ and $T = 2T = 2n$ Now, the amount will be
$\text{A}=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{2\text{n}}$
$C = A - P$
So, half the given annual rate and double the given number of years.
Hence, option $(d)$ is correct
View full question & answer→MCQ 1741 Mark
The cost of the article was Rs. $15500$ and Rs. $500$ was spent on its repairing. If it is sold for a profit of $15 \%$. The selling price of the article is:
- A
Rs. $17400$
- ✓
Rs. $18400$
- C
Rs. $19400$
- D
Rs. $16400$
AnswerCorrect option: B. Rs. $18400$
Total cost $= 15500 + 500 = 16000$
$\text{Profit %}=\Big(\frac{\text{Profit}}{\text{Cost price}}\Big)\times100$
$\text{Profit}=\Big(\frac{\text{Profit%}\times\text{Cost price}}{100}\Big)$
$\text{P}=\frac{\big(15\times16000\big)}{100}=2400$
Selling Price = Profit + cost price $= 2400 + 16000 =$ Rs. $18400$
View full question & answer→MCQ 1751 Mark
$40\%$ of $50$ students of a class are good at Science. How many students are not good at Science?
Answer$\because$ Out of $100$ good at Science $= 40$
$\therefore$ Out of $50$ good at Science
$=\frac{40}{100}\times50=20$
or
Number of student good at science
$= 40 \%$ or $50\ %$ $=\frac{40}{100}\times50=20$
Number of student not good at science
$= 50 - 20 = 30$
View full question & answer→MCQ 1761 Mark
Tick $(\checkmark)$ the correct answer in the following: The compound interest on Rs $10000$ at $12 \%$ per annum for $112112$ years, compounded annually, is.
- ✓
Rs. $1872$
- B
Rs. $1720$
- C
Rs. $1910.16$
- D
Rs. $1782$
AnswerCorrect option: A. Rs. $1872$
Principal $(P)$ = Rs. $10000$
Rate $(r) = 12\%\ p.a$
Period (n) $=1\frac{1}{2}\text{year}$
$\therefore $ Amount (A) $=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }10000\Big(1+\frac{12}{100}\Big)^1\Big(1+\frac{12}{2\times100}\Big)$
$=\text{Rs. }10000\times\frac{28}{25}\times\frac{53}{50}$
$=\text{Rs. }11872$
$\therefore$ $C.I = A - P =$ Rs. $11872 - 10000$
= Rs. $1872$
View full question & answer→MCQ 1771 Mark
A teak tree was planted $3$ years ago. The rate of its growth is $30\ %$ per annum. If at present. the height of the tree is $670\ cm$, what wad its height when it was planted?
- A
$300\ cm$
- B
$250\ cm$
- C
$315\ cm$
- ✓
$305\ cm$
AnswerCorrect option: D. $305\ cm$
Height of the tree after $t$ years $t'$ years $=\text{p}\Big(1+\frac{\text{R}}{100}\Big)$
Here the tree was planted $3$ years ago
So height of the tree after $3$ years is the [present height of the tree
Let $x$ represent the height of the tree $3$ years ago.
$\Rightarrow 670=\text{x}\Big(1+\frac{30}{100}\Big)^3$
$\Rightarrow670=\text{x}\Big(\frac{13}{10}\Big)^3$
$\Rightarrow\text{x}=\frac{670\times1000}{2107}$
$\Rightarrow\text{x}=305$
View full question & answer→MCQ 1781 Mark
The compound interest on Rs. $50,000$ at $4\%$ per annum for $2$ years compounded annually is:
- A
Rs. $4,000$
- ✓
Rs. $4,080$
- C
Rs. $4,280$
- D
Rs. $4,050$
AnswerCorrect option: B. Rs. $4,080$
Given, principal $(P) =$ Rs. $50000$
Rate of interest $(R\%) = 4\%$ per annum
Time period $(T) = 2$ yr
We know that,
$\text{A}=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{T}}$
$\text{A}=50000\Big(1+\frac{4}{100}\Big)^2$
$=50000\Big(1+\frac{1}{25}\Big)^2=50000\times\frac{26}{25}\times\frac{26}{25}$
$= 60 \times 25 \times 26 =$ Rs. $54080$
Compound interest, $CI = A − p =$ Rs. $54080$ − Rs. $50000$
= Rs. $4080$
View full question & answer→MCQ 1791 Mark
Tick $(\checkmark)$ the correct answer in the following:On selling $100$ pencils a man gains the selling price of $20$ pencils. His gain percent is:
- A
$20\%$
- ✓
$25\%$
- C
$22\frac{1}{2}\%$
- D
$16\frac{2}{3}\%$
AnswerCorrect option: B. $25\%$
Let the $SP$ of $100$ pens be Rs $x$.
$SP$ of $1$ pen $=\text{Rs. }\frac{\text{x}}{100}$
Profit $=\text{Rs. }\frac{\text{20x}}{100}$
$=\text{Rs. }\frac{\text{x}}{5}$
Now, $CP$ $=\text{x}-\frac{\text{x}}{5}=\frac{4\text{x}}{5}$
$\therefore$ Gain percentage $=\frac{\frac{\text{x}}{5}}{\frac{4\text{x}}{5}}\times100=25\%$
View full question & answer→MCQ 1801 Mark
Tick $(\checkmark)$ the correct answer in the following: The value of a machine depreciates at the rate of $10\%$ per annum. It was purchased $3$ years ago for Rs. $60000$. What is the present value of the machine?
- A
Rs. $53640$
- B
Rs. $51680$
- ✓
Rs. $43740$
- D
Rs. $43470$
AnswerCorrect option: C. Rs. $43740$
$3$ years ago, the value of machine = Rs. $60000$
Rate of depreciation $(R) = 10\%$
Period $(n) = 3$ years
$\therefore$ Present value $=\text{P}\Big(1-\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }60000\Big(1-\frac{10}{100}\Big)^3$
$=\text{Rs. }60000\times\Big(\frac{9}{10}\Big)^3$
$=\text{Rs. }60000\times\frac{9}{10}\times\frac{9}{10}\times\frac{9}{10}$
$=\text{Rs. }43740$
View full question & answer→MCQ 1811 Mark
Tick $(\checkmark)$ the correct answer in the following: $(180\%$ of $?) ÷ 2 = 504$.
Answer$\Big(\frac{180}{100}\times\text{x}\Big)\div2=504$
$\Rightarrow180\text{x}\div2=50400$
$\Rightarrow9\text{x}=560$
View full question & answer→MCQ 1821 Mark
Tick $(\checkmark)$ the correct answer in the following: The compound interest on Rs. $4000$ at $10\%$ per annum for $2$ years $3$ months, compounded annually, is.
- A
Rs. $1331$
- ✓
Rs. $3310$
- C
Rs. $3130$
- D
Rs. $13310$
AnswerCorrect option: B. Rs. $3310$
Principal $(P) =$ Rs. $10000$
Rate $(r) = 10\%\ p.a$
Period $(n) = 3$ years
$\therefore $ Amount (A) $=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }10000\Big(1+\frac{10}{100}\Big)^3$
$=\text{Rs. }10000\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}$
$=\text{Rs. }13310$
$\therefore$ $C.I = A - P =$ Rs. $13310 - 10000$
$= Rs. 3310$
View full question & answer→MCQ 1831 Mark
Shyam bought a second hand refrigerator for Rs. $2,500$, then spent Rs. $500$ on its repairs and sold it for Rs. $3,300$. Find his loss or gain per cent.
- A
Loss $15\%\ 2a$
- B
Loss $10\%$
- ✓
Profit $10\%$
- D
AnswerCorrect option: C. Profit $10\%$
Profit $10\%$
View full question & answer→MCQ 1841 Mark
The salary of Manish is Rs. $10000$ His salary gets increased by $10\%$. Find his increased salary.
- A
Rs. $9000$
- ✓
Rs. $11000$
- C
Rs. $8000$
- D
Rs. $12000$
AnswerCorrect option: B. Rs. $11000$
Increase in salary
$=10000\times\frac{10}{100}=\text{Rs.}1000$
$\therefore$ Increased salary
$=$ Rs. $10000 +$ Rs. $1000 =$ Rs. $11000$
View full question & answer→MCQ 1851 Mark
Suraj bought a car for Rs. $4.50.000$. Next year its price decreased by $20\%$ and further next year it decreased by $28\%$. In the two years, overall decrease per cent in the price of the car is:
- A
$43.6\%$
- B
$43.1\%$
- C
$42\%$
- ✓
$42.4\%$
AnswerCorrect option: D. $42.4\%$
Price of car = Rs. $4,50,000$
Decrease of price in first year = $20\%$
$=\frac{20}{100}\times 4,50,000=\text{Rs. }90,000$
Therefore, price after $1$ year = Rs. $4,50,000 - 90,000$ = Rs. $2.25,000$
Similarly, the price of car after second year $=3,60,000-\frac{28}{100}\times3,60,000$
= Rs. $3,60,000$ - Rs. $1,00,800$ = Rs. $2,59,200$
Total decrease in price = Rs. $90,000 + 1.00,800$ = Rs. $1,90,800$
Decrease percent $=\frac{190800}{450000}\times100= 42.4\%$
View full question & answer→MCQ 1861 Mark
A shopkeeper purchased $300$ bulbs for Rs. $10$ each. However $10$ bulbs were fused and had to be thrown away. The remaining were sold at Rs. $12$ each. Find the gain or loss $\%$.
AnswerCorrect option: C. $16\%$
$16\%$
View full question & answer→MCQ 1871 Mark
At what rate per cent per annum will Rs. $5000$ amount to Rs. $5832$ in $2$ years, compounded annually?
- A
$11\%$
- B
$10\%$
- C
$9\%$
- ✓
$8\%$
Answer$\text{A}=\text{Rs}.\ \text{P}\times\Big(1+\frac{\text{R}}{100}\Big)^\text{n}$
$\Rightarrow\text{Rs}.\ 5932=\text{Rs}.\ 5000\times\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow\frac{\text{Rs. }5832}{\text{Rs. }5000}=\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow\Big(\frac{27}{25}\Big)^2=\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow1+\frac{\text{R}}{100}=\frac{27}{25}$
$\Rightarrow\frac{\text{R}}{100}=\frac{27}{25}-1$
$=\frac{27-25}{25}=\frac{2}{25}$
$\therefore\text{R}=\frac{100\times2}{25}=8\%$
View full question & answer→MCQ 1881 Mark
If $60\%$ of $x$ is $1200$, then the value of $‘x’$ is:
- A
$1000$
- ✓
$2000$
- C
$3000$
- D
$4000$
AnswerCorrect option: B. $2000$
$2000$
View full question & answer→MCQ 1891 Mark
A toy marked at Rs. $40$ is available for Rs. $32$. What per cent discount is given on the marked price?
- A
$10\%$
- ✓
$20\%$
- C
$25\%$
- D
$40\%$
AnswerCorrect option: B. $20\%$
Discount $= 40 - 32 =$ Rs. $8$
$\therefore$ Discount on Rs. $40$ = Rs. $8$
$\therefore$ Discount on Rs. $100$
$=\frac{80}{100}\times10=\text{Rs. }20$
View full question & answer→MCQ 1901 Mark
$40\%$ of $[100 – 20\%$ of $300]$ is equal to:
Answer$40%$ of $[100-20\%$ of $300]$
$=\frac{40}{100}\times\Big[100-\frac{20}{100}\times300\Big]$
$=\frac{40}{100}[100-60]$
$=\frac{40}{100}\times40=4\times4=16$
Hence, option $(b)$ is correct
View full question & answer→MCQ 1911 Mark
What time period is taken when interest is calculated half yearly?
- ✓
Twice as much as the number of given years.
- B
Half as much as the number of given years.
- C
Same as the number of given years.
- D
AnswerCorrect option: A. Twice as much as the number of given years.
There are $2$ conversion period in a year in terms of interest for half yearly,
So, two is multiplied by the time period when we have to calculate interest in half yearly.
Therefore, time period is taken when interest is calculated half yearly is twice as much as the number of given years.
For example: If time is $6$ months.
Then half yearly is months.
View full question & answer→MCQ 1921 Mark
Vimla purchased a watch for Rs. $500$ She sold it at a loss of $20\%$. Find the selling price.
- A
Rs. $500$
- ✓
Rs. $400$
- C
Rs. $300$
- D
Rs. $200$
AnswerCorrect option: B. Rs. $400$
$100 - 20 = 80$
$\because$ If $C.P.$ is $100$, then $S.P.$ = Rs. $80$
$\therefore$ If $C.P.$ is $500,$ then $S.P$
$=\frac{80}{100}\times500=\text{Rs. }400$
View full question & answer→MCQ 1931 Mark
Which of the following is a direct tax?
- A
- B
- ✓
- D
None of these
AnswerA direct tax is a tax, which is levied on the income or profits of the person who pays it, rather than on goods or services. A direct tax is paid directly by an individual or organisation to an imposing entity.
A taxpayer, for example, pays direct taxes to the government for different purposes, including real property tax, personal property tax, income tax or taxes on assets.
Therefore, income tax is a direct tax.
Hence, option $C$ is correct.
View full question & answer→MCQ 1941 Mark
Sapna purchased a cycle for $Rs. 1000$ and sold it for $Rs. 1200.$ Find her gain$\%.$
- ✓
$20\%$
- B
$10\%$
- C
$40\%$
- D
$12\%$
AnswerCorrect option: A. $20\%$
Gain $= 1200 - 1000 = 200$
$\therefore$ Gain$\%$ $=\frac{200}{1000}\times100\%=20\%$
View full question & answer→MCQ 1951 Mark
Suppose for the principal $P,$ rate $R\%$ and time $T,$ the simple interest is $S$ and compound interest is $C$. Consider the possibilities.
$i. C > S$
$ii. C = S$
$iii.C < S$
Then
AnswerCorrect option: A. only $(i)$ is correct.
Let the principle $(p) = Rs.100$
Rate of interest $(R) = 100\%$ and time period$(T) = 2 Yr.$
Then, simple interest$=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{100\times10\times2}{100}=\text{Rs}.20$
$\text{A}=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^\text{T}=100\Big(1+\frac{10}{100}\Big)^2$
$=100\times\frac{11}{10}\times\frac{11}{10}=\text{Rs}.20$
Compound interest, $CI = A - P = Rs. 121 - Rs. 100 = Rs. 21$
So, $C > S$
Hence, option $(a) $is correct.
View full question & answer→MCQ 1961 Mark
Out of $40$ students, $25\%$ passed in a class. How many students did actually pass$?$
Answer$25\%$ of $40\%$ $=\frac{25}{100}\times40=10$
View full question & answer→MCQ 1971 Mark
Tax on imports is an example of $............$
AnswerAny restriction imposed on the free flow of trade is a trade barrier. Trade barriers can either be tariff barriers $($the levy of ordinary negotiated customs duties in accordance with Article $\text{II}$ of the $\text{GATT})$ or non$-$tariff barriers, which are any trade barriers other than tariff barriers
Tax on imports is an example of Trade Barrier.
View full question & answer→MCQ 1981 Mark
The simple interest of $Rs. 500$ at the rate of $5\%$ is $Rs. 100.$ This interest is of the time.
- A
$1$ year
- ✓
$4$ years
- C
$10$ years
- D
$20$ years
AnswerCorrect option: B. $4$ years
$\frac{500\times5\times\text{T}}{100}=100$
$\Rightarrow\text{T}=\frac{100\times100}{500\times5}=4$
View full question & answer→MCQ 1991 Mark
The CIon $Rs. 8000$ for $1$ year at $5\%$ p.a. payable half-yearly is:
- A
$Rs. 810$
- B
$Rs. 400$
- ✓
$Rs. 405$
- D
$Rs. 810$
AnswerCorrect option: C. $Rs. 405$
$Rs. 405$
View full question & answer→MCQ 2001 Mark
Kanti purchased a sewing machine for $Rs. 2000.$ She sold it at a loss of $40\%$. Find the selling price.
- ✓
$Rs. 1200$
- B
$Rs. 400$
- C
$Rs. 800$
- D
$Rs. 2800$
AnswerCorrect option: A. $Rs. 1200$
$100 - 40 = 60$
$\because$ If $C.P.$is $Rs. 100,$ then $S.P. = Rs. 60$
$\therefore$ If $C.P.$is $Rs. 2000,$ then $S.P.$
$=\frac{60}{100}\times2000=\text{Rs.}1200$
View full question & answer→