2 Marks Questions

Question 12 Marks

Tell what property allows you to compute $\frac{1}{3} \times\left(6 \times \frac{4}{3}\right)$ as $\left(\frac{1}{3} \times 6\right) \times \frac{4}{3}$.

Answer

Since $a \times(b \times c)=(a \times b) \times c$ shows the associative property of multiplications. $\therefore \frac{1}{3} \times\left(6 \times \frac{4}{3}\right)=\left(\frac{1}{3} \times 6\right) \times \frac{4}{3}$ shows the associative property of multiplication.

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Question 22 Marks

Name the property under multiplication used in each of the following.: $\frac{-19}{29} \times \frac{29}{-19}=1$

Answer

Multiplicative inverse property

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Question 32 Marks

Name the property under multiplication used in each of the following.: $-\frac{13}{17} \times \frac{-2}{7}=\frac{-2}{7} \times \frac{-13}{17}$

Answer

Commutative property of multiplication

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Question 42 Marks

Find $\frac{3}{7}+\left(\frac{-6}{11}\right)+\left(\frac{-8}{21}\right)+\left(\frac{5}{22}\right)$

Answer

Commutative property of multiplication

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Question 52 Marks

Find $\quad \frac{2}{5} \times \frac{-3}{7}-\frac{1}{14}-\frac{3}{7} \times \frac{3}{5}$

Answer

$\begin{aligned} \frac{2}{5} \times \frac{-3}{7}-\frac{1}{14}-\frac{3}{7} \times \frac{3}{5} & =\frac{2}{5} \times \frac{-3}{7}-\frac{3}{7} \times \frac{3}{5}-\frac{1}{14} \quad \text { (by commutativity) } \\ & =\frac{2}{5} \times \frac{-3}{7}+\left(\frac{-3}{7}\right) \times \frac{3}{5}-\frac{1}{14} \\ & =\frac{-3}{7}\left(\frac{2}{5}+\frac{3}{5}\right)-\frac{1}{14} \quad \text { (by distributivity) } \\ & =\frac{-3}{7} \times 1-\frac{1}{14}=\frac{-6-1}{14}=\frac{-1}{2}\end{aligned}$

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Maths 2 Marks Questions

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