MCQ 11 Mark
Statement-1 (A): The area of the isosceles triangle is $\frac{5}{4} \sqrt{11} cm^2$, if the perimeter is 11 cm and the base is 5 cm.
Statement-2 (R): The area of the equilateral triangle is $20 \sqrt{3} cm^2$ whose each side is 8 cm.
Statement-2 (R): The area of the equilateral triangle is $20 \sqrt{3} cm^2$ whose each side is 8 cm.
- AStatement-1 and Statement-2 are True; Statement-2 is a correct explanation for Statement-1.
- BStatement-1 and Statement-2 are True; Statement-2 is not a correct explanation for Statement-1.
- ✓Statement-1 is True, Statement-2 is False.
- DStatement-1 is False, Statement-2 is True.
Answer
View full question & answer→Correct option: C.
Statement-1 is True, Statement-2 is False.
(c)
We have base $(a)=5 cm$. Let the length of each equal side be $b cm$. Then,
$\text { Perimeter }=11 cm \Rightarrow a+b+a=11 \Rightarrow 2 b+5=11 \Rightarrow 2 b=6\Rightarrow b=3 cm$
$\therefore$ $\text { Area }=\frac{a}{4} \sqrt{4 b^2-a^2}=\frac{5}{4} \sqrt{4 \times 9-25}=\frac{5}{4} \sqrt{11}cm^2$
So, statement-1 is true.
The area of the equilateral triangle whose each side is 8 cm is
$A=\frac{\sqrt{3}}{4} \times 8^2 cm^2=16 \sqrt{3} cm^2$
So, statement-2 is not true. Hence, option (c) is correct.
We have base $(a)=5 cm$. Let the length of each equal side be $b cm$. Then,
$\text { Perimeter }=11 cm \Rightarrow a+b+a=11 \Rightarrow 2 b+5=11 \Rightarrow 2 b=6\Rightarrow b=3 cm$
$\therefore$ $\text { Area }=\frac{a}{4} \sqrt{4 b^2-a^2}=\frac{5}{4} \sqrt{4 \times 9-25}=\frac{5}{4} \sqrt{11}cm^2$
So, statement-1 is true.
The area of the equilateral triangle whose each side is 8 cm is
$A=\frac{\sqrt{3}}{4} \times 8^2 cm^2=16 \sqrt{3} cm^2$
So, statement-2 is not true. Hence, option (c) is correct.
