Question 12 Marks
Complete the following equations which describe nuclear charge-
a. ${ }_{11}^{23} N a+{ }_0^1 n \rightarrow \ldots+{ }_{-1}^0 e$
a. ${ }_{11}^{23} N a+{ }_0^1 n \rightarrow \ldots+{ }_{-1}^0 e$
b. ${ }_4^9 Be +{ }_2^4 He \rightarrow{ }_0^1 n+$___ $\qquad$
c. ${ }_8^{16} O +{ }_0^1 n \rightarrow \ldots+{ }_2^4 He$
Answer
View full question & answer→In any nuclear reaction, mass number (no. of $p ^{+}+$no. of $n ^{\circ}$ ) and atomic number (no. of $p^{+}$) must be conserved.
1. (${ }_{11}^{23} N a+{ }_0^1 n \rightarrow \ldots+{ }_{-1}^0 e$;(mass no. A = 23+1=24, atomic no. $Z =11+1=12$, Magnesium having mass no. $24 \&$ atomic no. 12 ); ${ }_{11}^{23} Na +{ }_0^1 n \rightarrow{ }_{12}^{24} Mg +{ }_{-1}^0 e$
2. ${ }_4^9 Be +{ }_2^4 He \rightarrow{ }_0^1 n+\ldots$ (mass no. $A =9+4-1=12$, atomic no. $Z =4+2-0=6$, Carbon having mass no. $12 \&$ atomic no. 6 ); ${ }_4^9 Be +{ }_2^4 He \rightarrow{ }_0^1 n+{ }_6^{12} C$
3. ${ }_8^{16} O +{ }_0^1 n \rightarrow \ldots+{ }_2^4 He$ (mass no. $A =16+1=17$, atomic no. $Z =8-2=6$, isotopes of Carbon having mass no. $13 \&$ atomic no. 6); ${ }_8^{16} O +{ }_0^1 n \rightarrow{ }_6^{13} C +{ }_2^4 He$
1. (${ }_{11}^{23} N a+{ }_0^1 n \rightarrow \ldots+{ }_{-1}^0 e$;(mass no. A = 23+1=24, atomic no. $Z =11+1=12$, Magnesium having mass no. $24 \&$ atomic no. 12 ); ${ }_{11}^{23} Na +{ }_0^1 n \rightarrow{ }_{12}^{24} Mg +{ }_{-1}^0 e$
2. ${ }_4^9 Be +{ }_2^4 He \rightarrow{ }_0^1 n+\ldots$ (mass no. $A =9+4-1=12$, atomic no. $Z =4+2-0=6$, Carbon having mass no. $12 \&$ atomic no. 6 ); ${ }_4^9 Be +{ }_2^4 He \rightarrow{ }_0^1 n+{ }_6^{12} C$
3. ${ }_8^{16} O +{ }_0^1 n \rightarrow \ldots+{ }_2^4 He$ (mass no. $A =16+1=17$, atomic no. $Z =8-2=6$, isotopes of Carbon having mass no. $13 \&$ atomic no. 6); ${ }_8^{16} O +{ }_0^1 n \rightarrow{ }_6^{13} C +{ }_2^4 He$

