37 questions · timed · auto-graded
$^{58}_{26}\text{A},\ ^{58}_{28}\text{B}$
$^{79}_{35}\text{X},\ ^{80}_{35}\text{Y}$
Atoms of the same element can have different numbers of neutrons, the different possible versions of each element are called isotopes. ${^{58}\text{A}}_{26}\text{ and }^{58}\text{B}_{28}$ are not isotopes because they have different atomic numbers.
${^{79}\text{X}}_{26}\text{ and }^{80}\text{Y}_{35}$ are isotopes as they have same atomic number.
$^{58}_{26}\text{A},\ ^{58}_{28}\text{B}$
$^{79}_{35}\text{X},\ ^{80}_{35}\text{Y}$
In Na+ ion, there are only 10 electrons. The electronic configuration is 2, 8.
Therefore, the number of valence electrons in sodium ion is 8.
In O2- ion, there will be 10 electrons, as it has gained two electrons. The electronic configuration is 2, 8.
Therefore, the number of valence electrons in O2- is 8.
Example: The total no. of protons in a carbon atom is 6, so its atomic no. is 6.
Also, one atom of Na contains 11 protons and 12 neutrons, so its mass no. is 23.
X | Y | |
Protons | 8 | 8 |
Neutrons | 8 | 9 |
Electrons | 8 | 8 |
$^1_1\text{H},\ ^2_1\text{H},\ ^3_1\text{H}$
Explain why:A | B | |
Protons | 18 | 20 |
Neutrons | 22 | 20 |
$\text{Atom B}-{^{209}\text{A}}_{83}$
$35=\frac{35\text{x}}{100}+\frac{37(100-\text{x})}{100}$
$\text{x}=75$