MCQ 511 Mark
In the figure, the perimeter of $\triangle\text{ABC}$ is:
- ✓$30\ cm$
- B$60\ cm$
- C$45\ cm$
- D$15\ cm$
Answer
By the property of tangent
$AO = AR = 4\ cm ($tangent from $A)$
$BR = BP = 6\ cm ($tangent from $B)$
$PC = CQ = 5\ cm ($tangent from $C)$
Perimeter of $\triangle\text{ABC}$ $= AB + BC + CA$
Perimeter of $\triangle\text{ABC}$ $= AR + BR + BP + PC + CQ + QA$
Perimeter of $\triangle\text{ABC}$ $= 4 + 6 + 6 + 5 + 5 + 4$
Perimeter of $\triangle\text{ABC}$ $= 30\ cm$
View full question & answer→Correct option: A.
$30\ cm$
By the property of tangent
$AO = AR = 4\ cm ($tangent from $A)$
$BR = BP = 6\ cm ($tangent from $B)$
$PC = CQ = 5\ cm ($tangent from $C)$
Perimeter of $\triangle\text{ABC}$ $= AB + BC + CA$
Perimeter of $\triangle\text{ABC}$ $= AR + BR + BP + PC + CQ + QA$
Perimeter of $\triangle\text{ABC}$ $= 4 + 6 + 6 + 5 + 5 + 4$
Perimeter of $\triangle\text{ABC}$ $= 30\ cm$