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Question 11 Mark
By Changing one variable in to another variable in solving pair of linear equations is called method of substitution. (Creamer rule, Elimination, Substitution)
Answer
Substitution
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Question 21 Mark
The linear equations in two variables has infinite solutions if lines are ____________ (coincident, parallel, intersecting)
Answer
coincident
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Question 31 Mark
Normally, the condition that $a$ and $b$ both equally zero can be described by ___________$\left(a^2-b^2 \neq 0, a^2+b^2 \neq 0,-a^2+b^2 \neq 0\right)$
Answer
$a^2+b^2 \neq 0 $
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Question 41 Mark
The sum of $5$ chairs and $2$ tables is $₹ 4850$, then from it the linear equations in two variables will be __________$(5 x-2 y=4850,2 x+5 y=4850,5 x+2 y=4850)$
Answer
$5x+2y=4850$
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Question 51 Mark
By which number have to multiply the equation $x+2 y=5$ into equation $(i)$ and $2 x+3 y=7$ from equation (ii) to eliminate $y ? \quad\left(\frac{-3}{3}, \frac{2}{3}, \frac{3}{2}\right)$
Answer
$\frac{-3}{2}$
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Question 61 Mark
The sum of $1 kg$ tea and $7 kg$. sugar is $₹ 480$, then from it the linear equation in two variables will be _______________ $(x-7 y=480, x+7 y=480,7 x+y=480)$
Answer
$x+7y=480$
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Question 81 Mark
The sum of the present age of Shashin and Hitesh is 58 years. Then, the pair of linear equations in two variables is __________ $(x-y=58, x+y=58,2 x-y=58)$
Answer
$x+y=58$
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Question 91 Mark
In standard form the equation $\frac{x}{2}-\frac{y}{3}=1$ can be written as _________$(3 x+2 y+6=0,-3 x+2 y-6=0,3 x-2 y-6=0)$
Answer
$3x-2y-6=0$
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Question 101 Mark
For pair of linear equations in two variables when $\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$, then we get _______ solutions. (infinite, consistent, inconsistent)
Answer
infinite
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Question 111 Mark
Two lines are intersecting in one point, then this type of pair is_________ (inconsistent, consistent, infinity)
Answer
consistent
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Question 121 Mark
The general form of pair of linear equations in two is______ $\left(a x-b y-c=0\right.$ where $a \neq 0, b \neq 0, a^2+b^2 \neq 0 ; a x_1+b y+c=0$ where $a \neq 0, b \neq 0, a^2+b^2 \neq 0 ; a x-$ $b y+c=0$ where $a \neq 0 \quad b \neq 0, a^2+b^2=0$ )
Answer
$a x+b y+c=0$, where $a \neq 0, b \neq 0$ and $a^2+b^2 \neq 0$
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Question 131 Mark
Shilpa went to the stationary shop and purchased $3$ pencils and $2$ pens and pays $₹ 25$, then pair of linear equations in two variables is________ $(3 x-2 y=25,3 x+2 y=-25,3 x+2 y=25)$
Answer
$3x+2y=25$
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Question 161 Mark
The present age of father and his son is $x$ years and y years respectively. After $8$ years, father's age will be $\frac{5}{2}$ times the age of his son. It is represented by______$x+8=\frac{5}{2}(y+8), x-8=\frac{5}{2}(y-8), x+8=\frac{5}{2}(y-8))$
Answer
$x+8=\frac{5}{2}(y+8)$
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Question 171 Mark
The sum of a two digit number and the number formed by interchanging its digit is always divisible by_____ $(10,11,101)$
Answer
$11$
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Question 181 Mark
In a two digit number, the unit's digit is $(a-1)$ and the ten's digit is $(a+1)$ Then this number is_______ $(11 a-9,9 a+11,11 a+9)$
Answer
$11a+9$
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Question 191 Mark
The present age of mother and her daughter is $x$ years and $y$ years respectively. The difference of their reciprocal is$\left(\frac{x y}{x-y}, \frac{x-y}{x y}, \frac{x+y}{x y}\right)$
Answer
$\frac{x-y}{x y}$
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Question 201 Mark
$\frac{5}{x}+\frac{3}{y}=24$ and $\frac{3}{x}+\frac{5}{y}=16$ then $\frac{1}{x}+\frac{1}{y}=\ldots \ldots . .(x \neq 0, y \neq 0)(10,15,5)$
Answer
$5$
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Question 211 Mark
If the graph of the equation $2 x+3 y=p$ is passing through the origin then $p=\ldots \ldots \ldots . .(0,1,2)$
Answer
$0$
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Question 221 Mark
The sum of two numbers is $10$ and their difference is $2$ . Then the larger number is ......... $(6,8,10$ )
Answer
$6$
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Question 251 Mark
If the solution of the equations $3 a+2 b=13$ and $a+3 b=9$ is $(3, k)$ then $k=\ldots \ldots \ldots . .(2,4,6)$
Answer
$2$
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Question 281 Mark
$2$ tube and $3$ value to gather cost $₹ 350$, where as $3$ tube and $2$ value together cost $₹ 500$ The cost of one tube and one value together is_______ $(170,180,190)$
Answer
$170$
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Question 301 Mark
If $5 x+3 y=24$ and $3 x+5 y=8$ then $x-y=$_______ (Without finding the vlues of $x, y$ )
$(12,8,4)$
Answer
$8$
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Question 311 Mark
If the solution of the equations $3(k-1) x+4 y=24$ and $15 x+20 y=8(k+13)$ is infinite then $k=$_______ $(2,-2,1)$
Answer
$2$
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Question 321 Mark
If the pair of linear equations $a_1 x+b_1 y+c_1=0$ and $a_2 x+b_2 y+c_2=0$ has unique solution then $\frac{y}{x}$=______
$\left(\frac{ a _1 b _2- a _2 b _1}{1}, \frac{ b _1 c _1- b _2 c _1}{ a _1 b _2- a _2 b _1}, \frac{ c _1 a _1- c _2 a _1}{ b _1 c _2- b _2 c _1}\right)$
Answer
$\frac{c_1 a_2-c_2 a_1}{b_1 c_2-b_2 c_1}$
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Question 331 Mark
If the pair of linear equations $a_1 x+b_1 y+c_1=0$ and $a_2 x+b_2 y+ c _2=0$ has unique solution then $y=$_________
${\left[\frac{ c _1, a _2- c _2 a _1}{ a _1, b _2- a _2 b _1}, \frac{ b _1 c _1- b _2 c _1}{ a _1 b _2- a _2 b _2} \text {, where } a_1 b_2-a_2 b_1 \neq 0 \text {, where } a, b_2-a_2 b_1 \neq 0 \frac{ a _1 b _2- a _2 b _1}{1}\right]}$
Answer
$=\frac{b_1 c_2-b_2 c_1}{a_1 b_2-a_2 b_1}, a_1 b_2-a_2 b_1 \neq 0$
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Question 341 Mark
If the pair of linear equations $a_1 x+b_1 y+c_1=0$ and $a_2 x+ b _2 y+ c _2=0$ has unique solution then $x=$___________
${\left[\frac{ c _1, a _2- c _2 a _1}{ a _1, b _2- a _2 b _1}, \frac{ b _1 c _1- b _2 c _1}{ a _1 b _2- a _2 b _2}, \text { where } a_1 b_2-a_2 b_1 \neq 0 \text {, where } a, b_2-a_2 b_1 \neq 0 \frac{ a _1 b _2- a _2 b _1}{1}\right]}$
Answer
$\frac{b_1 c_2-b_2 c_1}{a_1 b_2-a_2 b_1}, a_1 b_2-a_2 b_1 \neq 0$
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Question 351 Mark
If the pair of linear equations $a_1 x+b_1 y+c_1=0$ and $a_2 x+b_2 y+ c _2=0$ has unique solution then $\frac{x}{y}=$________$
\left(\frac{ b _1 c _1- b _2 c _1}{ b _1 b _2- b _2 b _1}, \frac{ c _1 a _1- c _2 a _1}{ a _1 b _2- a _2 b _1}, \frac{ a _1 b _2- a _2 b _1}{1}\right)
$
Answer
$\frac{b_1 c_2-b_2 c_1}{c_1 a_2-c_2 a_1}$
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Question 361 Mark
If the equations $3 x+y=1$ and $(2 k-1) x+(k-1) y=2 k+1$ are inconsistent then $k=$________$(-2,2,1)$
Answer
$2$
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Question 371 Mark
If the graph of the linear equations $3 x+2 k y=2$ and $2 x+5 y+1=0$ represents parallel lines then $k=$ _____________$\left(\frac{15}{4}, \frac{4}{15}, \frac{3}{5}\right)$
Answer
$\frac{15}{4}$
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Question 391 Mark
If the solution of the pair of the linear equations $a x+2 y=7$ and $2 x+3 y=8$ is unique then $a \neq$ ____________$\left(\frac{3}{4}, \frac{4}{3}, \frac{2}{3}\right)$
Answer
$\frac{4}{3}$
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Question 401 Mark
If $(5,3)$ is the solution of the equation $2 x+3 y+k=0$ and $(m, 5)$ is also the solution of it then $m$ $=$_______$(2,-2,5)$
Answer
$2$
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Question 411 Mark
If one of the solution of $x+2 y-4=0$ is $(2, k)$ then find the value of $k=$___________ $(0,1,-1)$
Answer
$1$
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Question 461 Mark
For pair of linear equations two variables $a_1 x+b_1 y$ $+c_1=0$ and $a_2 x+b_2 y=c_2=0, \frac{a_1}{a_2} \neq \frac{b_1}{b_2}$, then pair of equation has one and only one solution.
Answer
True
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Question 491 Mark
For pair of linear equations two variables $a_1 x+b_1 y$ $+c_1=0$ and $a_2 x+b_2 y=c_2=0, \frac{a_1}{a_2} \neq \frac{b_1}{b_2}$, then pair of equation has one and only one solution.
Answer
true
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True False[1 Marks ] - Maths STD 10 Questions - Vidyadip