Without using trignometric tables, prove that:
$\text{cosec }^272^\circ-\tan^218^\circ=1$
View full solution →$\text{cosec }^272^\circ-\tan^218^\circ=1$
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Prove that:
$\cot\theta\tan(90^\circ-\theta)-\sec(90^\circ-\theta)\text{cosec }\theta\\+\sqrt{3}\tan12^\circ\tan60^\circ\tan78^\circ=2$
Prove that:
$\cos15^\circ\cos35^\circ\text{cosec }55^\circ\cos60^\circ\text{cosec }75^\circ=\frac{1}{2}$
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