Questions · Page 2 of 2

2 Mark Each

Question 522 Marks
Find 10 th term of geometric progression : $\frac{1}{27},-\frac{1}{9}, \frac{1}{3},-1, \ldots$
Answer
$-729$
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Question 582 Marks
The first term of a G.P. is 2 and its common ratio is $\frac{1}{\sqrt{2}}$. Find its 13 th term.
Answer
$\frac{1}{32}$
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Question 592 Marks
The first term of a G.P. is 81 and its common ratio is $-\frac{1}{\sqrt{3}}$. Find its 11th term.
Answer
$\frac{1}{3}$
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Question 602 Marks
The first term of a G.P. is $\frac{243}{64}$ and its common ratio is $\frac{4}{9}$ Find its 6th term.
Answer
$\frac{16}{243}$
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Question 612 Marks
The first term of a G.P. is 625 and its common ratio Is $\frac{1}{5}$, Find its 8 th term.
Answer
$\frac{1}{\frac{1}{125}}$
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Question 642 Marks
Which term of G.P. $\frac{2}{9}, \frac{1}{3}, \frac{1}{2}, \frac{3}{4}, \ldots \ldots \ldots$ will be $\frac{81}{32}$ ?
Answer
7 th
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Question 662 Marks
The 4 th term of a G.P. $=0.0081$ and its common ratio is $0.3$. Find the first term of the G.P.
Answer
$0.3$
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Question 672 Marks
The common ratio and the fifth term of a $G.P$ are $3$ and $324$ respectively , Find the first term of the $G.P.$
Answer
In the given $G.P...,$ the common ratio $r=3$, the fifth term is $324$ i..e, $T=324$ and we required the first term of the $G.P.$ i.e. a.
Here,$T_5=324$
$\therefore a r^{5-1}=324\left(\therefore T_n=a r^{n-1}\right)$
$\therefore a(3)^4=324(\therefore r=3)$
$\therefore a \times 81=324$
$\therefore a =\frac{ 3 2 4 }{ 8 1 }=4$
Hence, the first term of the $G.P.$ is $4.$
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2 Mark Each - Page 2 - Statistics STD 11 Commerce Questions - Vidyadip