Question 13 Marks
If $P(n)$ is the statement "$n^2 + n$ is even", and if $P(r)$ is true, then $P(r + 1)$ is true.
Answer
View full question & answer→$P(n): n^2+n$ is even Given, $P(r)$ is true $\Rightarrow r^2+r$ is even $\Rightarrow r^2+r=2 \lambda \ldots(1)$ Now, $(r+1)^2+(r+1)=r^2+1+2 r+r$
$+1=(r+1)^2+2 r+2=2 \lambda+2 r+2\left[\right.$ Using equation (1)] $=2(\lambda+r+1)=2 \lambda \Rightarrow(r+1)^2+(r+1)$ is even $\Rightarrow P(r$ +1 ) is true
$+1=(r+1)^2+2 r+2=2 \lambda+2 r+2\left[\right.$ Using equation (1)] $=2(\lambda+r+1)=2 \lambda \Rightarrow(r+1)^2+(r+1)$ is even $\Rightarrow P(r$ +1 ) is true